Question

在下面的简化示例中，对物种Zombie的所有objects过滤生物数组。目前，回调函数filterCreatures只能搜索Zombie这个词。但是，我想传递一个具有不同生物名称的变量，以便我可以重复使用该函数来搜索每种类型的怪物。例如，它看起来像return a.species === creatureType;我该怎么做？有没有办法用.filter()传递额外的变量？非常感谢！

'use strict';
	
var creatures = [], zombieCreatures = [];
	
var filterCreatures;
	
creatures = [
  {species: 'Zombie', hitPoints: 90},
  {species: 'Orc', hitPoints: 40},
  {species: 'Skeleton', hitPoints: 15},
  {species: 'Zombie', hitPoints: 85}
];
	
filterCreatures = function(a) {
  return a.species === 'Zombie';
}
	
zombieCreatures = creatures.filter(filterCreatures);

console.log(zombieCreatures);

Answer 1

你可以创建这样的东西。创建一个取filter属性并返回实际过滤函数的函数。

＆＃13;

'use strict';
	
var creatures = [], zombieCreatures = [];
	
var filterFactory;
	
creatures = [
  {species: 'Zombie', hitPoints: 90},
  {species: 'Orc', hitPoints: 40},
  {species: 'Skeleton', hitPoints: 15},
  {species: 'Zombie', hitPoints: 85}
];
	
filterFactory = function(filter) {
  return function(a) {
     return a.species === filter;
  };
};
	
zombieCreatures = creatures.filter(filterFactory('Zombie'));

console.log(zombieCreatures);

zombieCreatures = creatures.filter(filterFactory('Orc'));

console.log(zombieCreatures);

＆＃13;

Answer 2

您可以使用bind这样的功能

filterCreatures = function(creatureType, a) {
  return a.species === creatureType;
}

zombieCreatures = creatures.filter(filterCreatures.bind(null, 'Zombie'));

Answer 3

可以通过稍微修改代码来完成。

创建一个接受任何数组的函数和一个要过滤的元素

var creatures = [],
  zombieCreatures = [];

var filterCreatures;

creatures = [{
    species: 'Zombie',
    hitPoints: 90
  },
  {
    species: 'Orc',
    hitPoints: 40
  },
  {
    species: 'Skeleton',
    hitPoints: 15
  },
  {
    species: 'Zombie',
    hitPoints: 85
  }
];

function filterCreatures(array, crt) {
  return array.filter(function(a) {
    return a.species === crt;
  })
}


console.log(filterCreatures(creatures, 'Skeleton'));

有没有办法通过或.filter（）传递一个额外的参数？

3 个答案: