Question

我现在已经尝试了一段时间，我只是放弃了。我想从数字中提取数据（无论它是否是大写字母）。差不多，我试图摆脱每一行的模特和生日，但更难的是，它是一个字符串。我把它隔开只是为了让它更容易阅读。

我试图在REGEX java中找到答案。这就是我正在尝试但是，当然正在删除第一个数字（4,66）之后的整个字符串

[;]。[MO] *

提前谢谢！

输入：

Type:Carro;high:4,66;model:fourDoors;birthday:01/01/1980

type:Truck;high:5,66;model:twoDoors;birthday:29/05/1977

tYpe:motorcycle;high:1,55;model:fiveDoors;birthday:01/01/1980

type:Carro;high:4,66;type:model;birthday:6/12/1887

type:Carro;high:9,66;model:Doors;birthday:05/12/2010

预期OutPut：

Type:Carro;high:4,66

type:Truck;high:5,66

tYpe:motorcycle;high:1,55

type:Carro;high:4,66 

type:Carro;high:9,66

Answer 1

希望这对你有用。有几种方法可以使这些代码略微缩小，但这至少应该有助于让您走上正确的道路。

我把它放在一个main方法中，但很容易将它放入自己的函数中。这将允许您传递任意数量的数组。

我在代码中的注释中添加了所有逻辑，我希望它有所帮助：

public static void main(String[] args) {

    /*Get your strings into an Array*/
    String[] str = {"Type:Carro;high:4,66;model:fourDoors;birthday:01/01/1980",
                    "type:Truck;high:5,66;model:twoDoors;birthday:29/05/1977",
                    "tYpe:motorcycle;high:1,55;model:fiveDoors;birthday:01/01/1980",
                    "type:Carro;high:4,66;type:model;birthday:6/12/1887",
                    "type:Carro;high:9,66;model:Doors;birthday:05/12/2010",
                    "Expected OutPut:",
                    "Type:Carro;high:4,66",
                    "type:Truck;high:5,66",
                    "tYpe:motorcycle;high:1,55",
                    "type:Carro;high:4,66",
                    "type:Carro;high:9,66"
    };
    /*Create a "final staging" array*/
    String[] newStr = new String[str.length - 1];

    for (int j = 0; j < str.length - 1; j++) {//For each of your strings
        str[j] = str[j].toLowerCase();//set the string to lower

        /*If they don't contain a semi-colon and a model or birthday reference go to else*/
        if (str[j].contains(";") && str[j].contains("model") || str[j].contains("birthday")) {
            /*Otherwise, split the string by semi-colon*/
            String[] sParts = str[j].split(";");

            String newString = "";//the new string that will be created

            for (int i = 0; i < sParts.length - 1; i++) {//for each part of the sParts array

                if (sParts[i].contains("model") || sParts[i].contains("birthday")) {//if it contains what is not desired
                    //Do Nothing
                } else {
                    newString += sParts[i];//otherwise concatenate it to the newString
                }

                newStr[j] = newString;//add the string to the "final staging" array
            }
        } else {

            newStr[j] = str[j];//if it didn't have semi-colons and birthday or model, just add it to the "final staging" array

        }

    }

    for (String newS : newStr) {// finally if you want to see the "final staging" array data... output it.

        System.out.println(newS);

    }

}

输出

type:carrohigh:4,66
type:truckhigh:5,66
type:motorcyclehigh:1,55
type:carrohigh:4,66
type:carrohigh:9,66
expected output:
type:carro;high:4,66
type:truck;high:5,66
type:motorcycle;high:1,55
type:carro;high:4,66

如果我碰巧错过了要求中的某些内容，请告诉我，我很乐意解决它。

Answer 2

String str =＆＃34;类型：Carro;高：4,66;型号：四门;生日：01/01 / 1980，类型：卡车;高：5,66;型号：两门;生日：29 / 05/1977，类型：摩托车;高：1.55;型号：fiveDoors;生日：01/01/1980，类型：卡罗;高：4,66;类型：模型;生日：6 /一千八百八十七分之十二＆＃34; ;

StringTokenizer tokens = new StringTokenizer(str, ",");
while (tokens.hasMoreTokens()) {
    String token = tokens.nextToken() ;

    StringTokenizer tokens2 = new StringTokenizer(token, ":");
    while (tokens2.hasMoreTokens()) {
        String key = tokens2.nextToken() ;
        if (key.equalsIgnoreCase("type")){
            System.out.println("locate: "+key+"\n");
        }
    }

}

如何从头到尾删除短语

2 个答案: