Question

在代码中：

skill = input("Which skill would you like to increase by 1 ?: ")
            for x in abilities:
                if x.lower() == skill.lower():
                    abilities[x] += 1
                    break
            print("Sorry, I don't see that skill...")

和字典是：

abilities = {
    "STR" : 10,
    "DEX" : 10,
    "CON" : 10,
    "INT" : 10,
    "WIS" : 10,
    "CHR" : 10 }

然后，当输入字符串“STR”被输入时，我得到响应，告诉我字符串不相同。

据我所知，他们是？这里有一个非常简单的错误，我不小心查看了，或者这种事情是否存在某种规则？

Answer 1

for x in abilities:
    if x.lower() == skill.lower():
        abilities[x] += 1
        break
print("Sorry, I don't see that skill...")

无论循环结果如何，都会打印错误消息。

只需在else循环中添加for即可

for x in abilities:
    if x.lower() == skill.lower():
        abilities[x] += 1
        break
else:
    # called when for loop ended without hitting break or return
    print("Sorry, I don't see that skill...")

然而，这是一种非常低效的计算方式，你不是按原样使用字典，而是作为tuples的列表，所以线性搜索，非常低效

使用（没有循环）：

skill = skill.upper()  # so casing matches the keys
if skill in abilities:
  abilities[x] += 1

Answer 2

你知道abilities＆＃39;键都是大写字符串，因此您应该将输入转换为大写：

skill = input("Which skill would you like to increase by 1 ?: ").upper()
if skill in abilities:
    abilities[x] += 1
else:
    print("Sorry, I don't see that skill...")

为什么这两个字符串不一样，字典和输入？

2 个答案: