Question

已经坚持了大约一个小时。目前正在尝试使用Python自学编程。我正在使用教科书编写的东西，它引导我通过伪代码然后我尝试将其转换为python以学习语法。虽然编程运行并按预期添加，但如果用户输入除整数之外的任何内容，它将不会打印我想要的内容。

Pseudocode我在看：

1  Declare Count As Integer 
2  Declare Sum As Integer 
3  Declare Number As Float 
4  Set Sum = 0 
5  For (Count = 1; Count <=10; Count++) 
6    Write “Enter an integer: “ 
7    Input Number 
8    If Number != Int(Number) Then
9      Write “Your entry is not an integer.” 
10      Write “The summation has ended.” 
11      Exit For 
12    Else 
13 Set Sum = Sum + Number 
14    End If 
15  End For 
16  Write “The sum of your numbers is: “ + Sum

这是我写到这一点的代码：

sum = 0
for count in range(0, 10):
    number = int(input("Write an integer: "))
    if number != int(number):
        print ("Your entry is not an integer.")
        print ("The summation has ended.")
        break
    else:
        sum = sum + number
    continue
print("The sum of your numbers is: " + str(sum))

Answer 1

如果int(arg)不是整数，arg函数会抛出异常。

您需要捕获异常：

number = input()
try:
    number = int(number)
except ValueError:
    print "Number is not an integer"

Answer 2

你可以这样做：

sum = 0

for count in range(1, 10):
    try:
        sum += int(input("Write an integer: "))
    except ValueError:
        print("Your entry is not an integer.")
        print("The summation has ended.")
        break

print("The sum of your numbers is: " + str(sum))

检查用户输入是否为int（python）

2 个答案: