Question

我正在尝试通过使用另一个列表进行for循环来检查列表中字符串的数量。我在list1中搜索双精度索引，但我的问题是，一旦在列表中找到第一个字符串，当找到第二个实例时索引不会上升。我希望在这种情况下0,1,2,3，但实际上它是0,1,1,3。

list1 = ['ABBA', 'CBBA', 'CBBA','DBBA']
list2 = ['ABBA','CBBA','DBBA']

for line in list1:
    for marker in list2:
        if marker in line:
            print("Marker found", list1.index(line))

Answer 1

您可以enumerate列表，以便知道哪一行是哪个索引：

lines = ['ABBA', 'CBBA', 'CBBA','DBBA']
markers = ['ABBA','CBBA','DBBA']

for index, line in enumerate(lines):
    for marker in markers:
        if marker in line:
            print("Marker found", index)

输出：

Marker found 0
Marker found 1
Marker found 2
Marker found 3

比较列表之间的内容和数量

1 个答案: