Question

我有三张表，products，customers，order

产品：

id | name |
 1 | milk |
 2 | bread|
 3 | Pea  |

客户：

id | name  | category
1  | James | retailer
2  | Paul  | vendor
3  | Dave  | retailer

订单：

id  | product_id | customer_id | qty | price
 1  | 1          | 2           | 23  | 50 
 2  | 2          | 2           | 4   | 30
 3  | 3          | 2           | 6   | 10
 4  | 2          | 1           | 9   | 30
 5  | 3          | 1           | 2   | 10
 6  | 1          | 3           | 6   | 50
 7  | 3          | 3           | 7   | 10

当我执行查询以显示类别为vendor

的客户的交易时

SELECT customer.name, product.name as pname, order.qty, order.price FROM customer, product, order 
WHERE customer.id = order.customer_id 
AND product.id = order.product_id AND customer.category = "vendor"

我会得到类似的东西：

name |  pname | qty | price
Paul |  milk  | 23  | 50
Paul |  bread | 4   | 30
Paul |  pea   | 6   | 10

我想改为：

name | milk  | bread  | pea  | total
Paul | 23    | 4      | 6    | 90

零售商的看法如下：

SELECT customer.name, product.name as pname, order.qty, order.price FROM 
customer, product, order 
WHERE customer.id = order.customer_id 
AND product.id = order.product_id AND customer.category = "retailer"

我会得到一张这样的表：

 name |  pname | qty | price
James |  bread | 9   | 30
James |  pea   | 2   | 10
 Dave |  milk  | 6   | 50
 Dave |  pea   | 7   | 10

但我想改为：

name  | milk  | bread  | pea  | total
James | 0     |  9     | 2    | 40
Dave  | 6     |  0     | 7    | 60

Answer 1

只需使用条件聚合来旋转列。并且一定要使用显式连接而不是已弃用的隐式连接，因为前者已经成为ANSI-92中25年的标准。

SELECT c.name,  
       SUM(CASE WHEN p.name = 'milk' THEN o.qty ELSE 0 END) as milk,
       SUM(CASE WHEN p.name = 'bread' THEN o.qty ELSE 0 END) as bread,
       SUM(CASE WHEN p.name = 'pea' THEN o.qty ELSE 0 END) as pea,
       SUM(o.price) AS Total 
FROM `customer` c
INNER JOIN `order` o
  ON c.id = o.customer_id 
INNER JOIN `product` p
  ON p.id = o.product_id 
WHERE c.category = 'vendor'   -- same for retailer
GROUP BY c.name

Answer 2

我认为您不能直接从一个简单的选择

获得此响应结构

name  | milk  | bread  | pea  | total
James | 0     |  9     | 2    | 40
Dave  | 6     |  0     | 7    | 60

因为您的数据库在零售商/客户订单中占了一排。

我知道使用像PHP或Java这样的服务器语言，您可以按照自己的意愿处理数据并进行检索。

MySQL pivot将行放入列中

2 个答案: