解决方案

Question

我有两个表格InvoiceLocations和PCInvoiceLocation以及各自的数据。

我只想要输出如下。

请帮忙。

评论代码：

declare @@LocationId nvarchar(50)='1,2' 
declare @@sql nvarchar(Max) 
Declare @@Output table(Code nvarchar(10) not null) 
Set @@sql='SELECT Code FROM invoiceLocations WHERE Id IN ('+@LocationId+')' 
insert @@Output(Code) 
exec sp_executesql @sql

Answer 1

创建测试环境

首先，我使用以下命令创建测试环境

CREATE TABLE InvoiceLocations (ID int,CODE varchar(3), VALUE varchar(3));
CREATE TABLE PCInvoiceLOcation (ID int,CategoryID INT, Locations varchar(50),DefaultLocationID int);


INSERT INTO InvoiceLocations(ID,CODE,VALUE)
VALUES(1,'BFC','BFC'),
(2,'BRH','BRH'),
(3,'BRP','BRP'),
(4,'BCC','BCC')

INSERT INTO PCInvoiceLOcation(ID,CategoryID,Locations,DefaultLocationID)
VALUES(1,1,'1,2',1),
(2,2,'2,3',2),
(3,3,'2,1',1),
(4,4,'4',4)

解决方案

您可以通过3个步骤实现此目的：

首先将Locations字段拆分为行
使用InvoiceLocations表加入这些行以获取相关值
将结果汇总到逗号分隔的字段

首先将Locations字段拆分为行

;with tmp(ID,CategoryID,Locations,DefaultLocationID,  DataItem , Data) as (
        select ID,CategoryID,Locations,DefaultLocationID, 
                CAST( LEFT(Locations, CHARINDEX(',',Locations+',')-1) as varchar(5)),
                STUFF(Locations, 1, CHARINDEX(',',Locations+','), '')
        from PCInvoiceLOcation
    union all
        select ID,CategoryID,Locations,DefaultLocationID,  
                CAST(LEFT(Data, CHARINDEX(',',Data+',')-1) AS Varchar(5)),
                STUFF(Data, 1, CHARINDEX(',',Data+','), '')
        from tmp
        where Data > '')

使用InvoiceLocations表加入这些行以获取相关值

select tmp.ID,CategoryID,Locations,DefaultLocationID,  DataItem , InvoiceLocations.VALUE
from tmp
INNER JOIN InvoiceLocations ON tmp.DataItem = InvoiceLocations.ID

将结果汇总到逗号分隔字段

Select ID,CategoryID,Locations,DefaultLocationID,  
            STUFF((SELECT ', ' + VALUE
                       FROM Tmp2 AS T3 
                       WHERE T3.ID = tmp2.ID 
                      FOR XML PATH('')), 1, 2, '')
    FROM tmp2 
    GROUP BY ID,CategoryID,Locations,DefaultLocationID

整个查询将类似于

;with tmp(ID,CategoryID,Locations,DefaultLocationID,  DataItem , Data) as (
        select ID,CategoryID,Locations,DefaultLocationID, 
                CAST( LEFT(Locations, CHARINDEX(',',Locations+',')-1) as varchar(5)),
                STUFF(Locations, 1, CHARINDEX(',',Locations+','), '')
        from PCInvoiceLOcation
    union all
        select ID,CategoryID,Locations,DefaultLocationID,  
                CAST(LEFT(Data, CHARINDEX(',',Data+',')-1) AS Varchar(5)),
                STUFF(Data, 1, CHARINDEX(',',Data+','), '')
        from tmp
        where Data > '')
    ,tmp2(ID,CategoryID,Locations,DefaultLocationID,  DataItem , VALUE) AS (
        select tmp.ID,CategoryID,Locations,DefaultLocationID,  DataItem , InvoiceLocations.VALUE
        from tmp
        INNER JOIN InvoiceLocations ON tmp.DataItem = InvoiceLocations.ID) 

        Select ID,CategoryID,Locations,DefaultLocationID,  
                STUFF((SELECT ', ' + VALUE
                           FROM Tmp2 AS T3 
                           WHERE T3.ID = tmp2.ID 
                          FOR XML PATH('')), 1, 2, '')
        FROM tmp2 
        GROUP BY ID,CategoryID,Locations,DefaultLocationID

结果：

SQLFiddle Demo

<强>参考

基于逗号分隔字段的内连接

1 个答案:

解决方案