Question

我试图在Python中编写一个方法，通过查找最小出现次数来查找哪个卡是最稀有的。我也试图返回与这些相关的名称和颜色。有人能帮我写一个更有效的方式吗？我可以计算出现次数，获取颜色并将它们放在列表中，然后在列表中获取名称。但除了把它放在所有单独的列表中之外，我怎么能这样做呢？我可以发布更多代码，但稀有类型是罕见，普通，稀有和神话罕见。

代码：

def get_rarest_card(self):
    uncommon_counter = 0
    common_counter = 0
    rare_counter = 0
    mythic_rare_counter =0
    mythic_rare_cards=[]
    uncommon_color_list=[]
    common_color_list=[]
    rare_color_list=[]
    mythicrare_color_list=[]

for eachCard in self.cardlist:
    if eachCard.rarity=="Uncommon":
        uncommon_counter = uncommon_counter + 1
        uncommon_color_list.append(eachCard.get_colors())
    elif eachCard.rarity=="Common":
        common_counter=common_counter + 1
        common_color_list.append(eachCard.get_colors())
    elif eachCard.rarity=="Rare":
        rare_counter = rare_counter + 1
        rare_color_list.append(eachCard.get_colors())
    elif eachCard.rarity=="Mythic Rare":
        mythic_rare_cards.append(eachCard.get_name())
        mythic_rare_counter = mythic_rare_counter + 1
        mythicrare_color_list.append(eachCard.get_colors())
return(mythic_rare_cards)

Answer 1

collections.Counter可以帮助您：

from collections import Counter
card_rarities = Counter(card.rarity for card in self.cardlist)
rarity = min(card_rarities, key=lambda card: card_rarities[card])  # Effectively an argmin
return [card for card in self.cardlist if card.rarity == rarity]

任何可以清洗的东西都可以通过这个过程，因此您可以获得最不常见的稀有，颜色或特定卡片，具体取决于您提供给Counter的内容。

Answer 2

def get_rarest_cards():
    return [card for card in self.cardlist if card.rarity.lower() == 'mythic rare']

如何打印它们取决于您。也许是名字？

mythics = my_cards.get_rarest_cards()
for card in mythics:
    print(card.get_name())

用于查找最小出现次数的Python方法

2 个答案: