假设我们有一张桌子DVD:
id title type
1 Star Wars Movie
2 Yellow Submarine Music
3 The Lord of The Rings Movie
4 Black Butterfly Music
我们希望获得电影'黑蝴蝶'的DVD,但如果列表中不存在,那么我们想要获得其他电影。 Firth请求:
Select * from DVDs where type='Movie' and title='Black Butterfly'
如果请求没有返回任何内容,则执行第二个请求。
Select * from DVDs where type='Moview'
目前,我正在使用(在Java中)2个查询模板和2个对数据库(Oracle)的请求。我正在寻找机会使用1个模板和1个请求。
答案 0 :(得分:2)
你可以这样做:
with b as (
Select *
from DVDs
where type = 'Movie' and title = 'Black Butterfly'
)
select b.*
from b
union all
select d.*
from dvd
where type = 'Movie' and not exists (select 1 from b);
或者,您可以使用窗口函数:
Select . . .
from (select d.*,
count(*) filter (where title = 'Black Butterfly') over () as cnt_bb
from DVDs d
where type = 'Movie'
) d
where cnt_bb = 0 or title = 'Black Butterfly';
答案 1 :(得分:2)
尝试:
DO
$do$
BEGIN
IF EXISTS (Select * from DVDs where type='Movie' and title='Black Butterfly') THEN
Select * from DVDs where type='Movie' and title='Black Butterfly';
ELSE
Select * from DVDs where type='Moview';
END IF;
END
$do$