我正在测试一个基本的事务案例,但它仍然停留在producer.initTransaction(); 任何配置都可能出错吗?
public static void main(String[] argv) throws Exception {
String topicName = "helloworldpartitioned";
// Configure the Producer
Properties configProperties = new Properties();
configProperties.put(ProducerConfig.BOOTSTRAP_SERVERS_CONFIG, "localhost:9092");
configProperties.put(ProducerConfig.KEY_SERIALIZER_CLASS_CONFIG, StringSerializer.class);
configProperties.put(ProducerConfig.VALUE_SERIALIZER_CLASS_CONFIG, StringSerializer.class);
configProperties.put(ProducerConfig.TRANSACTION_TIMEOUT_CONFIG, "1000");
configProperties.put(ProducerConfig.CLIENT_ID_CONFIG, "test");
// configProperties.put(ProducerConfig.ENABLE_IDEMPOTENCE_CONFIG, Boolean.TRUE);
configProperties.put(ProducerConfig.TRANSACTIONAL_ID_CONFIG, PRODUCER_TRANSACTIONAL_ID);
KafkaProducer<String, String> producer = new KafkaProducer<String, String>(configProperties);
producer.initTransactions();
producer.beginTransaction();
String line = "TestMessage";
System.out.println("Inizializzo la transazione");
ProducerRecord<String, String> rec = new ProducerRecord<String, String>(topicName, line);
producer.send(rec);
// Thread.sleep(5000);
producer.commitTransaction();
producer.flush();
producer.close();
}
答案 0 :(得分:0)
尝试:
producer.initTransactions();
producer.beginTransaction();
String line = "TestMessage";
System.out.println("Inizializzo la transazione");
ProducerRecord<String, String> rec = new ProducerRecord<String, String>(topicName, line);
producer.send(rec);
// Thread.sleep(5000);
producer.commitTransaction();
producer.flush();
producer.close();