Question

我正在尝试从文档标题列表中快速创建DITA keydef列表。如果标题是“设备用户指南”，我想创建一个这样的keydef：

<keydef keys="Device_User_Guide" class="+ map/topicref mapgroup-d/keydef ">
  <topicmeta class="- map/topicmeta ">
   <keywords class"- topic/keywords ">
    <keyword class="- topic/keyword ">Device User Guide</keyword>
   </keywords>
  </topicmeta>
</keydef>

标题是从titles.txt文件中提取的，其中每个都是新行。这导致键（Device_User_Guide）在末尾包含\ n，所以我的输出是这样的：

<keydef keys="Device_User_Guide
" class="+ map/topicref mapgroup-d/keydef ">
      <topicmeta class="- map/topicmeta ">
       <keywords class"- topic/keywords ">
        <keyword class="- topic/keyword ">Device User Guide</keyword>
       </keywords>
      </topicmeta>
    </keydef>

我设法用下划线替换空格并使用rstrip作为关键字，但是如何在我执行替换操作的同时剥离换行符？这是我的代码：

title = open('titles.txt', 'r')
keydefs = open('keydefs.txt', 'w')
for line in title:
    keydefs.write('<keydef keys="%s" class="+ map/topicref mapgroup-d/keydef ">\n  <topicmeta class="- map/topicmeta ">\n   <keywords class"- topic/keywords ">\n    <keyword class="- topic/keyword ">%s</keyword>\n   </keywords>\n  </topicmeta>\n</keydef>' % (line.replace(" ","_"), line.rstrip()))

Answer 1

我明白了。只需将line.rstrip()移动到循环的开头。

title = open('titles.txt', 'r')
keydefs = open('keydefs.txt', 'w')
for line in title:
    newline = line.rstrip()
    keydefs.write('<keydef keys="%s" class="+ map/topicref mapgroup-d/keydef ">\n  <topicmeta class="- map/topicmeta ">\n   <keywords class"- topic/keywords ">\n    <keyword class="- topic/keyword ">%s</keyword>\n   </keywords>\n  </topicmeta>\n</keydef>' % (newline.replace(" ","_"), newline))

从行中剥离/ n并同时在Python中执行替换

1 个答案: