Question

我需要以下查询的帮助，我将发布该表的示例。

     player | goals | gamedate

playername1 |  1    | 2011-01-01
playername2 |  2    | 2011-01-01
playername1 |  1    | 2011-01-02
playername3 |  1    | 2011-01-01
playername1 |  2    | 2011-01-03
playername1 |  1    | 2011-01-01
playername3 |  1    | 2011-01-01
playername2 |  2    | 2011-01-01
playername1 |  1    | 2011-01-04

还有更多的数据，我想知道如何编写一个查询，在一段时间（游戏季节）之间为顶级玩家提供最多的目标？

编辑：似乎我对数据结构的方式有误。对不起，我很抱歉。我将离开上一张桌子，以便每个人都可以看到第一个答案。我不想打开一个新问题，因为它基本上是一回事。我的道歉Haim。

`table1`
  id | gamedate

1    | 2011-01-01
2    | 2011-01-02
3    | 2011-01-03
4    | 2011-01-04
5    | 2011-01-05


`table2`
id | gameid  |      player | goals

 1 |   1     |  playername1 |  1  
 2 |   1     |  playername2 |  2  
 3 |   2     |  playername1 |  1 
 4 |   1     |  playername3 |  1
 5 |   3     |  playername1 |  2
 6 |   4     |  playername1 |  1
 7 |   2     |  playername3 |  1
 8 |   3     |  playername2 |  2
 9 |   5     |  playername1 |  1

gameid是由table1中的ID引用的外键。

Answer 1

替换您要检查的日期，并将限制（在示例中为5）设置为您想要的玩家数量。

SELECT player , sum(goals) AS top_scores FROM mytable 
WHERE gamedate BETWEEN '2011-01-02' AND '2011-01-07'
GROUP BY player ORDER BY top_scores DESC  LIMIT 5

编辑（根据问题编辑，你只需要添加一个连接）：

SELECT player , sum(goals) AS top_scores FROM table2 t2
LEFT JOIN table1 t1  ON t1.id = t2.gameid
WHERE gamedate BETWEEN '2011-01-02' AND '2011-01-07'
GROUP BY player ORDER BY top_scores DESC  LIMIT 5

在一定时间内计算最大值

1 个答案: