Question

我希望获取按商品ID对其进行分组的交易总额。我能够在Oracle DB中的查询下面获得所需的结果，但是在MYSQL中也不起作用。

以下错误是我得到的：

未知栏＆＃39; tran.itemid＆＃39;在＆＃39; on条款＆＃39;

SELECT tran.itemid, 
    (SELECT SUM(tranitm.quandity) 
        FROM transactions_item tranitm 
        JOIN transactions tr  
            ON(tr.id  = tranitm.transid and tranitm.itemid = tran.itemid) 
        where TR.TRANSTYPE = 1) Purchases, 
    (SELECT SUM(tranitm.quandity) 
        FROM transactions_item tranitm 
        JOIN transactions tr 
            ON(tr.id = tranitm.transid and tranitm.itemid = tran.itemid) 
        where TR.TRANSTYPE = 2 ) Sales, 
    (SELECT SUM(tranitm.quandity) 
        FROM transactions_item tranitm 
        JOIN transactions tr 
            ON(tr.id = tranitm.transid and tranitm.itemid = tran.itemid) 
        where TR.TRANSTYPE = 3 ) PurchasesRtn, 
    (SELECT SUM(tranitm.quandity) 
        FROM transactions_item tranitm 
        JOIN  transactions tr 
            ON(tr.id = tranitm.transid and tranitm.itemid = tran.itemid)
        where TR.TRANSTYPE = 4) SalesRtn 
FROM transactions_item tran 
GROUP BY tran.itemid

架构：

CREATE TABLE transactions
( id INT, transtype INT,fromledger INT,
 ledgerid INT,agentid INT, quandity FLOAT,rate FLOAT);

CREATE TABLE transactions_item
 (transid INT, itemid INT,quandity FLOAT,rate FLOAT);

INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (1, 1, 1, 1, 1, 100, 1000);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (2, 2, 1, 1, 1, 10, 1200);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (3, 3, 1, 1, 1, 50, 1500);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (4, 4, 1, 1, 1, 120, 1300);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (5, 1, 1, 1, 1, 10, 1100);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (6, 2, 1, 1, 1, 12, 1400);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (7, 3, 1, 1, 1, 130, 1550);
INsert into transactions (id, transtype, fromledger, ledgerid, agentid, 
 quandity, rate) values (8, 4, 1, 1, 1, 110, 1700);

INsert into transactions_item (transid, itemid,quandity,rate) values (1, 1, 100, 1000);
INsert into transactions_item (transid, itemid,quandity,rate) values (2, 1, 10, 1200);
INsert into transactions_item (transid, itemid,quandity,rate) values (3, 1, 50, 1500);
INsert into transactions_item (transid, itemid,quandity,rate) values (4, 1, 120, 1300);
INsert into transactions_item (transid, itemid,quandity,rate) values (5, 1, 10, 1100);
INsert into transactions_item (transid, itemid,quandity,rate) values (6, 1, 12, 1400);
INsert into transactions_item (transid, itemid,quandity,rate) values (7, 1, 130, 1550);
INsert into transactions_item (transid, itemid,quandity,rate) values (8, 1, 110, 1700);
INsert into transactions_item (transid, itemid,quandity,rate) values (1, 2, 100, 1000);
INsert into transactions_item (transid, itemid,quandity,rate) values (2, 2, 10, 1200);
INsert into transactions_item (transid, itemid,quandity,rate) values (3, 2, 50, 1500);
INsert into transactions_item (transid, itemid,quandity,rate) values (4, 2, 120, 1300);
INsert into transactions_item (transid, itemid,quandity,rate) values (5, 2, 10, 1100);
INsert into transactions_item (transid, itemid,quandity,rate) values (6, 2, 12, 1400);
INsert into transactions_item (transid, itemid,quandity,rate) values (7, 2, 130, 1550);
INsert into transactions_item (transid, itemid,quandity,rate) values (8, 2, 110, 1700);

Answer 1

子查询中的ON子句应该用于关联要连接的表。不属于联接的条件应该在WHERE。

但是，除了所有相关的子查询之外，还有更好的方法。

SELECT tran.itemid,
        SUM(IF(tr.transtype = 1, tran.quandity, 0)) AS Purchases,
        SUM(IF(tr.transtype = 2, tran.quandity, 0)) AS Sales,
        SUM(IF(tr.transtype = 3, tran.quandity, 0)) AS PurchasesRtn,
        SUM(IF(tr.transtype = 4, tran.quandity, 0)) AS SalesRtn
FROM transactions_item AS tran
JOIN transactions AS tr ON tran.transid = tr.id
GROUP BY tran.itemid

DEMO

请参阅need to return two sets of data with two different where clauses

查询中的MYSQL未知列

1 个答案: