我有一个输入文件格式:
(a n),(a n-1),...(a 0)
如何在Pascal
中形成如下所示的列表type
tt = ^t;
t = record
a: Integer;
n: Integer;
next: tt
end;
例如:
(5 10),(5 9),(5 8),(5 7),(5 6),(5 5),(5 4),(5 3),(5 2),(5 1), (5 0)
应该像图像上一样:
新代码(按预期工作):
program ex4_19;
type
tt = ^t;
t = record
a: Integer;
n: Integer;
next: tt
end;
var
ukzv, ukrs: tt;
inp: text;
raDone: boolean;
i: integer;
str: string;
begin
assign(inp, 'f1.txt'); reset(inp);
assign(output, 'out.txt'); rewrite(output);
new(ukzv);
ukrs:=ukzv;
read(inp, str);
writeln(str);
for i:=1 to length(str) do
begin
case str[i] of
'(':
begin
raDone:=false;
new(ukzv^.next);
ukzv:=ukzv^.next;
ukzv^.a:=0;
ukzv^.n:=0;
end;
'0' .. '9':
begin
if raDone = false then
ukzv^.a:=ukzv^.a * 10 + (ord(str[i]) - ord('0'))
else
ukzv^.n:=ukzv^.n * 10 + (ord(str[i]) - ord('0'));
end;
' ':
begin
if raDone = false then
begin
raDone:=true;
end;
end;
')':
begin
ukzv^.next:=nil;
end;
end;
end;
ukzv:=ukrs;
while ukzv^.next <> nil do
begin
writeln(ukzv^.next^.a, ' ', ukzv^.next^.n);
ukzv:=ukzv^.next;
end;
end.
我有错误&#34;数字格式无效&#34;因为在第二个数字后我们有&#39;。我不知道如何读取数字直到&#39;)&#39;因为数字可能不同(1-1000)。
答案 0 :(得分:1)
有不同的方式,一种是以下方式。首先将文件读入字符串变量。
'(5 10), (5 9), (5 8), (5 7), (5 6), (5 5), (5 4), (5 3), (5 2), (5 1), (5 0)'
然后使用循环(for..do
,repeat..until
或while..do
)逐个浏览字符。使用案例陈述来决定行动。
此处列出的每个字符的处理应该直接实现为case
语句。
您需要一个布尔值(例如raDone: boolean
)来指示新数字是否会转到记录中的a
或n
。
Get next char, '(', you know it's time to link in a new record (`r` in the following).
Get next char, '5', it's a digit and `not raDone`, so you accumulate `r.a` with it. See below!
Get next char, ' ', it's a space and `not raDone`, you know that entry for `r.a` has ended, set `raDone` to indicate next digits belong to `r.n`.
Get next char, '1', it's a digit and `raDone`, so you accumulate `r.n` with it.
Get next char, '0', it's a digit and `raDone`, so you accumulate `r.n` with it.
Get next char, ')', you know the entry for the current record is ready.
Get next char, comma, nothing to do, just skip it
Get next char, ' ', space, nothing to do, just skip it
使用十进制数字(从字符转换)累加二进制值(例如r.n):
r.n := r.n * 10 + (ord(decimal character) - ord('0');
您可能希望为输入字符串中的错误内容添加错误检查。