Question

我开发了以下代码，

public function getInCalls($sip_id){  

      $resultsTotalInCalls =  DB::table('xxxx')
    ->whereDate('created', '=', date('Y-m-d'))
    ->where(function ($query) {

    $query->where([
    ['event', '=', 'ENTERQUEUE'],
    ['agent', '=', $sip_id]

]);
    })

    ->get();  

     $numberofInCalls =  count($resultsTotalInCalls);   

     return $numberofInCalls;

}

但我在['agent', '=', $sip_id]行中得到了未定义的索引$ sip_id。如何将$ sip_id传递给函数？我不知道。

Answer 1

闭包需要从外部导入变量。

->where(function ($query) use ($sip_id) {

Answer 2

你应该试试这个：

public function getInCalls($sip_id){  

          $resultsTotalInCalls =  DB::table('xxxx')
        ->whereDate('created', '=', date('Y-m-d'))
        ->where(function ($query) use($sip_id) {

        $query->where([
        ['event', '=', 'ENTERQUEUE'],
        ['agent', '=', $sip_id]

    ]);
        })

        ->get();  

         $numberofInCalls =  count($resultsTotalInCalls);   

         return $numberofInCalls;

    }

Answer 3

如果您更喜欢使用闭包，那么您可以将变量导入当前范围（use关键字）：

https://stackoverflow.com/a/11086796/3520693

public function getInCalls($sip_id){

    $resultsTotalInCalls =  DB::table('xxxx')
        ->whereDate('created', '=', date('Y-m-d'))
        ->where(function ($query) use ($sip_id) {

            $query->where([
                ['event', '=', 'ENTERQUEUE'],
                ['agent', '=', $sip_id]

            ]);
        })

        ->get();

    $numberofInCalls =  count($resultsTotalInCalls);

    return $numberofInCalls;

}

Answer 4

public function getInCalls($sip_id){
    $resultsTotalInCalls =  DB::table('abc')
        ->whereDate('created', '=', date('Y-m-d'))
        ->where(function ($query) use ($sip_id) {
            $query->where([ ['event', '=', 'ENTERQUEUE'], ['agent', '=', $sip_id]  ]); 
        })
        ->get();  
    $numberofInCalls =  count($resultsTotalInCalls);
    return $numberofInCalls;  
}

未定义的索引错误Laravel 5.4其中的条款

4 个答案: