Question

程序要求用户输入要平均的数量

创建一个大小为数字（最大）的新数组
它将每个数字存储在数组条目
打印输入的数字
一行上有5个数字（使用打印件）
适当地使用println（使用％check）
打印所有数字的平均值

这是我需要做的，但我不认为我是正确的，因为我是java的新手这就是我到目前为止所做的：

import java.util.Scanner;

public class AnyAverageArr {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

    System.out.print("Please enter the max number:");

    int max = input.nextInt();

    int[] arr1 = new int[max];
    for (int i = 0; 1<= max; i++) {
        arr1[i] = input.nextInt();
    }


    System.out.println("Average of All is " + arr1[max]);

}
}

Answer 1

你一定要读一下java中的for循环。 https://docs.oracle.com/javase/tutorial/java/nutsandbolts/for.html

您还应该阅读平均值的含义。 https://www.reference.com/math/average-mean-mathematics-b2fb5e4b69989ed8

以下是对代码的简单快速修复

        Scanner input = new Scanner(System.in);

        System.out.print("Please enter the max number:");

        int max = input.nextInt();

        int sum = 0;

        for (int i = 0; i< max; i++) {
            sum += input.nextInt();
        }


        System.out.println("Average of All is " + sum / max);

Answer 2

首先需要保存数组中的所有元素。
然后你需要计算总和。
将总和除以元素总数。

以下是对您的代码的修复：

    Scanner input = new Scanner(System.in);
    System.out.print("Please enter the max number:");

    int numberOfElements = input.nextInt();

    int[] arr = new int[numberOfElements];
    int sum = 0;

    for (int i = 0; i< numberOfElements; i++) {
        arr[i] = input.nextInt();
        sum += arr[i];
    }

    System.out.println("Average of All is " + sum / numberOfElements);

我使用相同的循环来保存数组中的元素并同时计算总和。

希望这能解决您的问题

Answer 3

我了解您的要求，并且我的源代码更新了一点。我相信你可以遵循以下几点。

用户输入最大数量
用户想要输入avarage的数字，并且需要存储到数组中。
对数组元素求和并找到它的平均值。

请准确参考以下源代码。

public class StackOverflow {

	public static void main(String[] args) {
		
		 Scanner input = new Scanner(System.in);

		    System.out.print("Please enter the max number:");

		    int max = input.nextInt();

		    int[] arr1 = new int[max];
		    for (int i = 0; i < max; i++) {
		        arr1[i] = input.nextInt();
		    }
		    
		    int sum = 0;
		    for(int num : arr1){
		    	sum = sum + num;
		    }
		    
		    double avg = sum/max;
		    
		    System.out.println(" Avarage : " + avg);
	}
}

Answer 4

如果我没弄错的话，这就是你所需要的（解释见评论）：

try (Scanner input = new Scanner(System.in)) {
    System.out.print("Please enter the max number:");
    int max = input.nextInt();
    int[] arr1 = new int[max];
    for (int i = 0; i < max; i++) {
        arr1[i] = input.nextInt();
    }

    for (int i = 1; i <= max; i++) {
        System.out.print(arr1[i - 1] + " ");
        if (i % 5 == 0) {
            System.out.println();
        }
    }
    System.out.println();

    double sum = 0.0;
    for (int i = 0; i < max; i++) {
        sum += arr1[i];
    }
    System.out.println("Average: " + (sum / max));
} catch (Exception e) {
    e.printStackTrace();
}

Answer 5

import java.util.Scanner;

//here is your edited code
public class AnyAverageArr {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

    System.out.print("Please enter the max number:");

    int max = input.nextInt();

    int[] arr1 = new int[max];
    //since array starts from 0, we need to loop less than max
    //i< max : so loop will terminate when we will have input equals to max numbers
    for (int i = 0; i< max; i++) {
        arr1[i] = input.nextInt();
    }
    int sum=0;
    //loop again through array and calculate the sum of each number
    for(int v:arr1) {
        sum+=v;
    }
    //divide sum by total number of inputs to get the answer 
    System.out.println("Average of All is " + sum/max);

}
}

------------------------------------------------------------------------

Answer 6

您可以尝试以下代码：

public class StackOverflow {

  public static void main(String[] args) {
    try (Scanner input = new Scanner(System.in)) {
      System.out.print("Please enter the max number: ");
      int max = input.nextInt();

      // Creates a new array of the size as amount of numbers (max)
      int[] arr1 = new int[max];
      double sum = 0.0;

      // It stores each number in an array entry
      for (int i = 0; i < max; i++) {
        arr1[i] = input.nextInt();
        sum += arr1[i];
      }

      // Prints the numbers entered
      // 5 numbers on a line (use print)
      // Put a println appropriately (use % check)
      for (int i = 0; i < max; i++) {
        System.out.print(arr1[i] + " ");
      }

      // Print the average of all the numbers
      System.out.println();
      System.out.println("Average of all is " + sum / max);
    }
  }

}

如何创建数组以要求用户输入一定数量的数字，然后取平均值

6 个答案: