Question

我的数据库中有两个表。当我将记录插入第一个表时，我需要使用由Mysql自动生成的id并将其添加到第二个表中的新记录中。

所以我需要从这条记录中取id：

$sql = "INSERT INTO movies (title, year, format);

并将其放入此记录中：

$sql = "INSERT INTO actors(name, last_name, movi_id);
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                                              HERE

Answer 1

使用下面的内置PHP函数从上一个Insert Query中获取id：

mysqli_insert_id();

您的代码必须如下所示才能解决您的问题：

$sql = "INSERT INTO movies (title, year, format) VALUES ($title, $year, 
$format)";    
$movi_id = mysqli_insert_id();
$sql = "INSERT INTO actors(name, last_name, movi_id) VALUES ($name, 
$last_name, $movi_id)";

如果您可以在准备好的语句中写上述查询以使其更加安全，那就更好了：

// prepare and bind Movies Query
$queryMovies = $conn->prepare("INSERT INTO movies (title, year, format) 
VALUES (?, ?, ?)");
$queryMovies->bind_param("sss", $title, $year, $format);

// execute Movies Query
$queryMovies->execute();

// Get last inserted Id of Movies Query
$movi_id = $queryMovies->insert_id;

// prepare and bind Actors Query
$queryActors = $conn->prepare("INSERT INTO actors (name, last_name, movi_id) 
VALUES (?, ?, ?)");
$queryActors->bind_param("sss", $name, $last_name, $movi_id);

// execute Actors Query
$queryActors->execute();

// Close Connections
$queryMovies->close();
$queryActors->close();

Sql将id从一个表插入到另一个表中

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