Question

我试图根据分隔符解析字段，在这种情况下它是一个'|'。然后，将所有内容合并到同一个表中的其他字段（Parse1，Parse2等）中。下面的代码似乎非常接近，但它只能在我的TempTable中正确解析。出于某种原因，它不会更新FinalTable中的Parse1，Parse2，Parse3等

SELECT    DISTINCT
          split.a.value ('/A[1]', 'VARCHAR(MAX)') [Piece1],
          split.a.value ('/A[2]', 'VARCHAR(MAX)') [Piece2],
          split.a.value ('/A[3]', 'VARCHAR(MAX)') [Piece3],
          split.a.value ('/A[4]', 'VARCHAR(MAX)') [Piece4],
          split.a.value ('/A[5]', 'VARCHAR(MAX)') [Piece5],  
          split.a.value ('/A[6]', 'VARCHAR(MAX)') [Piece6],  
          split.a.value ('/A[7]', 'VARCHAR(MAX)') [Piece7]
 Field1,
 Field2,
 Field3
FROM [TempTable]
(
SELECT      CAST('<A>' + REPLACE(SrcID, '|', '</A><A>') + '</A>' AS XML) AS Data, Field1, Field2, Field3
FROM  dbo.FinalTable
) a cross apply Data.nodes('/A') AS split(a)

有没有人知道这有什么问题？

Answer 1

我尝试了下面的脚本，它应该可行。

    IF object_id('tempdb..#FinalTable') is not null drop table #FinalTable
    create table #FinalTable(SrcID varchar(max),Field1 int ,Field2 int ,Field3 int)
    insert into #FinalTable(SrcID,Field1,Field2,Field3)
    select 'a|b|c|d|e|f|g|h|i|j',1,2,3 union all
    select 'aa|sb|cc|bdn|ce|ffg|hjg|kh|ii|kj',1,2,3

    SELECT    DISTINCT
              split.a.value ('/A[1]', 'VARCHAR(MAX)') [Piece1],
              split.a.value ('/A[2]', 'VARCHAR(MAX)') [Piece2],
              split.a.value ('/A[3]', 'VARCHAR(MAX)') [Piece3],
              split.a.value ('/A[4]', 'VARCHAR(MAX)') [Piece4],
              split.a.value ('/A[5]', 'VARCHAR(MAX)') [Piece5],  
              split.a.value ('/A[6]', 'VARCHAR(MAX)') [Piece6],  
              split.a.value ('/A[7]', 'VARCHAR(MAX)') [Piece7],
     Field1,
     Field2,
     Field3
    FROM 
    (
    SELECT  CAST('<A>' + REPLACE(SrcID, '|', '</A><A>') + '</A>' AS XML) AS Data, Field1, Field2, Field3
    FROM  #FinalTable
    ) a cross apply Data.nodes('/A') AS split(a)

+--------+--------+--------+--------+--------+--------+--------+--------+--------+--------+
| Piece1 | Piece2 | Piece3 | Piece4 | Piece5 | Piece6 | Piece7 | Field1 | Field2 | Field3 |
+--------+--------+--------+--------+--------+--------+--------+--------+--------+--------+
| a      | b      | c      | d      | e      | f      | g      | 1      | 2      | 3      |
| aa     | sb     | cc     | bdn    | ce     | ffg    | hjg    | 1      | 2      | 3      |
+--------+--------+--------+--------+--------+--------+--------+--------+--------+--------+

Answer 2

我最终使用了这个。

CREATE FUNCTION [dbo].[SplitIndex](@Delimiter varchar(20) = ' ', @Search varchar(max), @index int)
RETURNS varchar(max)
AS
BEGIN
      DECLARE @ix int,
                  @pos int,
                @rt varchar(max)

      DECLARE @tb TABLE (Val varchar(max), id int identity(1,1))

      SET @ix = 1
      SET @pos = 1


      WHILE @ix <= LEN(@search) + 1 BEGIN

            SET @ix = CHARINDEX(@Delimiter, @Search, @ix)

            IF @ix = 0
                  SET @ix = LEN(@Search)
            ELSE
                  SET @ix = @ix - 1

            INSERT INTO @tb
            SELECT SUBSTRING(@Search, @pos, @ix - @pos + 1)

            SET @ix = @ix + 2
            SET @pos = @ix
      END

      SELECT @Rt = Val FROM @Tb WHERE id = @index
      RETURN @Rt     
END


SELECT dbo.SplitIndex(' ', 'hello big wide world', 1)
SELECT dbo.SplitIndex(' ', 'hello big wide world', 2)
SELECT dbo.SplitIndex(' ', 'hello big wide world', 3)
SELECT dbo.SplitIndex(' ', 'hello big wide world', 4)

效果很好!!

如何将一个字段解析为同一个表中的多个字段？

2 个答案: