我正在尝试使用Python提取Inventor部件(.ipt)的参数,使用以下代码:
#Open Inventor
invApp = win32com.client.Dispatch("Inventor.Application")
#Make inventor visible
invApp.Visible = True
#Set file names of template
Part_FileName_BaseIPT = 'C:\\Base.ipt'
#Open the base model
oPartDoc=invApp.Documents.Open(Part_FileName_BaseIPT)
#Collect parameters
oParams = oPartDoc.ComponentDefinition.Parameters
(这是我在此处找到的代码段的一部分:Using python to automate Autodesk Inventor)
我收到以下错误消息: ...'对象没有属性'ComponentDefinition'
任何想法都错了?
我是否必须以某种方式告诉Python oPartDoc与零件文档相关(而不是与装配文档相关)。在VBA中检索零件的参数将如下所示:
Dim partDoc As PartDocument
Set partDoc = ThisApplication.ActiveDocument
Dim param As Parameter
Set param = partDoc.ComponentDefinition.Parameters
我认为到目前为止,在Python代码中缺少VBA第一行中给出的信息。
这是Inventor API对象模型表的一部分,可能对解决方案有所帮助: API Object model
不幸的是,使用Python的Inventor API的记录非常糟糕,Autodesk论坛中的帖子也没有带来任何解决方案。但由于Python是我所知道的唯一编程语言,我必须依赖它。
我一直试图解决这个问题已经有一段时间了,任何帮助都会受到高度赞赏!
(我使用Inventor 2018,Python 3.6.2(Anaconda)和Windows 10。)
答案 0 :(得分:0)
我终于找到了解决方案,发明人帮助台发给我了:
import win32com.client
from win32com.client import gencache, Dispatch, constants, DispatchEx
oApp = win32com.client.Dispatch('Inventor.Application')
oApp.Visible = True
mod = gencache.EnsureModule('{D98A091D-3A0F-4C3E-B36E-61F62068D488}', 0, 1, 0)
oApp = mod.Application(oApp)
# oApp.SilentOperation = True
oDoc = oApp.ActiveDocument
oDoc = mod.PartDocument(oDoc)
#in case of an assembly use the following line instead
#oDoc = mod.AssemblyDocument(oDoc)
prop = oApp.ActiveDocument.PropertySets.Item("Design Tracking Properties")
# getting description and designer from iproperties
Descrip = prop('Description').Value
Designer = prop('Designer').Value
print("Description: ",Descrip)
print("Designer: ",Designer)
# getting mass and area
MassProps = oDoc.ComponentDefinition.MassProperties
#area of part
dArea = MassProps.Area
print("area: ",dArea)
#mass
mass = MassProps.Mass
print("mass: ",mass)
#getting parameters
oParams = oDoc.ComponentDefinition.Parameters
lNum = oParams.Count
print("number of Parameters: ",lNum)
# make sure the parameter names exist in the Inventor model
param_d0 = oParams.Item("d0").Value
print("Parameter d0: ",param_d0)
param_d1 = oParams.Item("d1").Value
print("Parameter d1: ",param_d1)
param_d2 = oParams.Item("d2").Value
print("Parameter d2: ",param_d2)
param_d0_exp = oParams.Item("d0").Expression
print("Parameter d0_exp: ",param_d0_exp)
param_d1_exp = oParams.Item("d1").Expression
print("Parameter d1_exp: ",param_d1_exp)
param_d2_exp = oParams.Item("d2").Expression
print("Parameter d2_exp: ",param_d2_exp)
autodesk社区网页上的原始帖子: