Question

使用PHP邮件功能发送邮件时出现此错误

错误是： - 在标题

中找不到收件人地址

请帮帮我

这是代码

//我的代码从这里开始

        $to  = navruk@gmail.com;
        $subject  = $_POST['txtsub'];
        $messgae  = $_POST['txtmessage'];
        $signature = $_POST['txtsignature'];
        $redirect = "thanks.php";
        $error    = "error.php";

            $body ="<table width='700' align='center' cellpadding='0' cellspacing='0' border='0'>
              <tr>
                <td valign='top'>
                      $messgae <br>
                </td>
              </tr>
              <tr>
                <td valign='top'>
                      $signature <br>
                </td>  
              </tr>
            </table>";

            $from      = "Aakrutisolutions<info@aakrutisolutions.com>";
            $headers  =  "From: $from\n";
            $headers .= 'MIME-Version: 1.0' . "\r\n";
            $headers .= "Content-type: text/html;charset=iso-8859-1\r\n"; 
            $headers .= "Content-Transfer-Encoding: 8bit\r\n";
            $headers .= "X-Priority: 1\r\n"; 
            $headers .= "X-MSMail-Priority: High\r\n"; 
            $headers .= "X-Mailer: Just My Server\r\n";
            $headers .= "".$body."\n";

                    if(mail($to, $subject, $message, $headers))
                    {
                        ?>
                        <script language="javascript">
                         location.href='bulkmail.php?sts=mailsent';
                        </script>
                        <?php
                    }
                    else
                    {
                        ?>
                        <script language="javascript">
                         location.href='bulkmail.php?sts=mailnotsent';
                        </script>
                        <?php

                    }

//我的代码在这里结束

Answer 1

我可以理解评论中的讽刺，从来没有那么少，我认为这样做是不行的，即使答案是显而易见的。很容易找到这些信息：

$headers = 'From: Navruk <navruk@gmail.com>' . "\r\n" .
           'To: Navruk1 <navruk@gmail.com>, Navruk2 <navruk@gmail.com>' . "\r\n" .
           'Cc: Navruk3 <navruk@gmail.com>' . "\r\n" .
           'Bcc: Navruk4 <navruk@gmail.com>' . "\r\n" .
           'Reply-To: noreply@example.com' . "\r\n" .
           'X-Mailer: PHP/' . phpversion();

mail(
       "navruk@gmail.com",
       "How to do basic mailing",
       "I can easily GOOGLE and find this LINK at the top http://php.net/manual/en/function.mail.php. Surprisingly, it is the PHP manual. If I CLICK this link I will find not only how to use the PHP command mail, but also a bunch of examples! This took me about 10 seconds to find.",
        $headers
      );

我建议你阅读邮件并自己尝试一下，你能打败我的10秒吗？！？

Answer 2

你的

$to  = navruk@gmail.com;

分配需要引用：

$to  = "navruk@gmail.com";

标头中找不到收件人地址

2 个答案: