Question

我想询问用户他们是否想在完成游戏时再次玩游戏。目前，他们这样做的唯一方法是再次调用该程序;但是，我想提醒用户他们是否想在游戏结束后再玩一次。

public class Hangman
{

    Random r;
    GetData get;
    String[] words = {"eat","what" };
    String word; 
    boolean finished = false;
    int badGuessCount=0;  
    boolean [] foundLetters;   
    String entryWord =" ";  

    public Hangman()
    {
      r = new Random();
      get = new GetData();
      playAGame();
    }

    public void playAGame()
    { 

        word = words[r.nextInt(words.length)];

        foundLetters = new boolean[word.length()];

        while (!finished)
        {
            showGallows(); 
            showWord();
            getGuess();
            checkGuess();
             if (badGuessCount==6)
             {
                 System.out.print('\u000C');
                 showGallows();
                 System.out.println("Sorry, but you lost.");
                 System.out.println("The word was: "+word);
                 finished=true;
             }
        }
    }

    public void showGallows()
    {
        System.out.print('\u000C');
        if (badGuessCount==0)
           man_0();
        if (badGuessCount==1)
           man_1();
        if (badGuessCount==2)
           man_2();
        if (badGuessCount==3)
           man_3();
        if (badGuessCount==4)
           man_4();
        if (badGuessCount==5)
           man_5();
        if (badGuessCount==6)
           completedMan();



        System.out.println("\n");
    }

    public boolean showWord()
    {
         boolean goodGuess = false;
         char ch = entryWord.charAt(0);
         for (int lc=0; lc < word.length(); lc++)
             if (foundLetters[lc]==true)
             {
               System.out.print(word.charAt(lc)+" ");
             }
             else if (word.charAt(lc)==ch)
                  {
                      System.out.print(word.charAt(lc)+" ");
                      foundLetters[lc] = true;
                      goodGuess = true;
                   }
                   else
                       System.out.print("_ ");
         return goodGuess;
    }

    public void getGuess()
    {
         System.out.println("\n\n\nWhat letter do you want to guess?");
         System.out.println("Type the whole word to guess the word.");
         System.out.println("You have "+(6 - badGuessCount)+ "guess left.");
         System.out.print("Enter guess");
         entryWord = get.aWord();
    }

    public void checkGuess()
    {
        boolean goodGuess; 
        if (entryWord.length()>1)
        {
            if (entryWord.equals(word))
            {
                System.out.println("\n\nYes You won!");
                finished = true;
                System.out.println("close and run if you want to play again!");
                String pause = get.aWord();
            }       
    }
    else
    {
        showGallows();
        goodGuess = showWord();
        if (goodGuess)
        {
            System.out.println("\n\n\nGood guess");
            System.out.println("Press the Enter key to continue!");
            String pause = get.aWord();
        }
            else
            {
            badGuessCount++;
            System.out.println("\n\n\nBad guess!");
            System.out.println("Press the Enter key to continue!");
            String pause = get.aWord();
            }
        }

    }   

    //public void completedMan()


}

如何提示用户再次播放，然后根据输入重启游戏？

Answer 1

您需要将Test::Test::Test本身放在循环中。

playAGame();

我建议使用do { playAGame(); } while (UserWantsToKeepPlaying()); private boolean UserWantsToKeepPlaying() { // Ask the user if they want to keep playing } - do循环，因为您将始终至少玩一次游戏，并且您（大概）不希望提示用户再次玩完玩游戏。

Answer 2

while时的错误（UserWantsToKeepPlaying（））;我想做什么

  do
  {
      playAGame();
  } while (UserWantsToKeepPlaying());
}

public boolean UserWantsToKeepPlaying(int number) 
{
  for (int i = 1; i > number; i--)
  if (number % i == 0 && i != number) return false;
  else return true;
  System.out.print("\n\n Play Again 'No' Press 0  Yes' Press 1 : ");
}

如何使用键盘接收单词重新启动java

2 个答案: