Question

我希望你很好，我已经在iphone上工作了几个星期，目前我有一个问题尝试用网址打开一个野生动物园，我有一个json文件来一个网址，这是一个dinamic。< / p>

这里我留下了代码。

- (void) loadFiles {

NSArray *_json = [[[self getDataFromJson] objectAtIndex:0] retain];
if ([_json count] > 0)
{
 for (int i = 0; i < [_json count]; i++)
 {
  NSDictionary *file = [_json objectAtIndex:i];

  UIImage *buttonImage = [UIImage imageNamed:@"btn.png"];
  UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom];
  [button setImage:buttonImage forState:UIControlStateNormal];

  [button addTarget:self action:@selector(openBrowser:) forControlEvents:UIControlEventTouchUpInside];

  //works but i have warnings
  button.tag = [file objectForKey:@"linkURL"] ;
  CGRect frame = CGRectZero;
  frame.size = buttonImage.size;
  button.frame = frame;

  NSString *name = [file objectForKey:@"name"];
  NSString *description = [file objectForKey:@"description"];


            //Create Box 

 }
}
}

- (void) openBrowser:(id)sender
{ 
 NSString *url = ((UIControl *) sender).tag;
 [[UIApplication sharedApplication]  openURL:[NSURL URLWithString:url] ];
}

我需要从UIButtom打开一个没有投诉的网址。任何建议或帮助，谢谢你。干杯

Answer 1

子类UIButton并添加一个属性来存储URL。

// MyButton.h
@interface MyButton : UIButton {
    NSString *urlString_;
}

@property (nonatomic, retain) NSString *urlString;

@end



// MyButton.m
#import "MyButton.h"

@implementation MyButton

@synthesize urlString = urlString_;

- (void)dealloc {
    [self setUrlString:nil];
    [super dealloc];
}

@end

然后继续使用您的代码：

#import "MyButton.h"
.
.
.
- (void) loadFiles {

    NSArray *_json = [[[self getDataFromJson] objectAtIndex:0] retain];
    if ([_json count] > 0)
    {
        for (int i = 0; i < [_json count]; i++)
        {
            NSDictionary *file = [_json objectAtIndex:i];

            UIImage *buttonImage = [UIImage imageNamed:@"btn.png"];
            MyButton *button = [MyButton buttonWithType:UIButtonTypeCustom];
            [button setImage:buttonImage forState:UIControlStateNormal];

            [button addTarget:self action:@selector(openBrowser:) forControlEvents:UIControlEventTouchUpInside];

            //works but i have warnings
            button.urlString = [file objectForKey:@"linkURL"] ;
            CGRect frame = CGRectZero;
            frame.size = buttonImage.size;
            button.frame = frame;

            NSString *name = [file objectForKey:@"name"];
            NSString *description = [file objectForKey:@"description"];


            //Create Box 

        }
    }
}

- (void) openBrowser:(id)sender {
    if ([sender isKindOfClass:[MyButton class]]) {
        [UIApplication sharedApplication] openURL:[NSURL URLWithString:[[(MyButton *)sender urlString]]];
    }
}

Answer 2

标签是一种int类型。所以你不能在这里存储NSString URL。您需要在其他地方存储URL，可能在NSMutableArray中。将索引i存储在按钮的标记中，并将URL存储在位置i的NSMutableArray中。然后在按钮处理程序中使用标记作为索引从该NSMutableArray获取URL。

与问题无关，你没有发布_json NSArray。所以你在泄漏记忆。而且您也不需要测试if ([_json count] > 0)。你的for循环已经处理了。

使用UIButton打开URL

2 个答案: