加入4副牌

Question

我有这个代码，我打算创建一组4个套牌，问题是在套装中，在卡片51之后，分割的结果给出4并且套装的数组不返回初始位置，我该如何解决这种情况？

谢谢

#include <stdio.h>
#define NCARTAS 52
int main()
{
    const char *numero[]= {"A","2","3","4","5","6","7","8","9","10","V","D","R"};
    const char *naipes[]= {"P","O","C","E"};
    char baralho[208];
    int posNumero,posNaipe;
    for(int i=0; i<208; i++)
    {
        baralho[i]=i;
        posNumero=i%13;
        posNaipe=i/13;

        printf("%s%s \n", numero[posNumero],naipes[posNaipe]);
    }  
}

Answer 1

posNaipe = i % NCARTAS / 13;

会这样做。这也是您了解运算符优先级和关联性的试金石。