如何在tkinter中放置框架以在表格中显示数据?

时间:2017-11-22 11:21:26

标签: python python-3.x tkinter

我需要在tkinter中使用框架或网格在表格中显示数据。 我已经在tkinter窗口中显示了数据,但我想放在一个表中,所以任何人都可以帮我处理代码(还有滚动条)..

这是代码:

       def allClub():
            data=cursor.execute("SELECT * from CLUBS order by club_name")


            master = Tk()
            master.geometry('500x500')
            master.title('CLUBS')
            Label1 = Label(master, text="CLUB ID", width=10)
            Label1.grid(row=0, column=0)
            Label2 = Label(master, text="CLUB NAME", width=10)
            Label2.grid(row=0, column=1)
            Label3 = Label(master, text="RATING", width=10)
            Label3.grid(row=0, column=2)
            Label1 = Label(master, text="MANAGER", width=10)
            Label1.grid(row=0, column=3)
            Label1 = Label(master, text="CHAIRMAN", width=10)
            Label1.grid(row=0, column=4)
            Label1 = Label(master, text="LEAGUE", width=15)
            Label1.grid(row=0, column=5)
            Label1 = Label(master, text="TITLES", width=10)
            Label1.grid(row=0, column=6)
            Label1 = Label(master, text="YEAR FOUNDED", width=10)
            Label1.grid(row=0, column=7)


            for index, dat in enumerate(data):
                Label(master, text=dat[0]).grid(row=index+1, column=0)
                Label(master, text=dat[1]).grid(row=index+1, column=1)
                Label(master, text=dat[2]).grid(row=index+1, column=2)
                Label(master, text=dat[3]).grid(row=index+1, column=3)
                Label(master, text=dat[4]).grid(row=index+1, column=4)
                Label(master, text=dat[5]).grid(row=index+1, column=5)
                Label(master, text=dat[6]).grid(row=index+1, column=6)
                Label(master, text=dat[7]).grid(row=index+1, column=7)

此处输出窗口的屏幕截图链接: https://i.stack.imgur.com/zFymD.jpg

2 个答案:

答案 0 :(得分:1)

Tkinter没有任何“表格”小部件,如果您计划有很多行和列,那么您可以使用的最好的事情是TreeviewListbox

另一方面,您无法为Frame创建滚动条,因为该小部件的文档并未说明它支持滚动。这个问题的解决方案涉及创建画布,您可以查看here

以下是Treeview小部件的示例:

from tkinter import *
from tkinter import ttk

root = Tk()
root.geometry("500x200")

data = [ ["val1", "val2", "val3"],
         ["asd1", "asd2", "asd3"],
         ["bbb1", "bbb3", "bbb4"],
         ["ccc1", "ccc3", "ccc4"],
         ["ddd1", "ddd3", "ddd4"],
         ["eee1", "eee3", "eee4"] ]


frame = Frame(root)
frame.pack()

tree = ttk.Treeview(frame, columns = (1,2,3), height = 5, show = "headings")
tree.pack(side = 'left')

tree.heading(1, text="Column 1")
tree.heading(2, text="Column 2")
tree.heading(3, text="Column 3")

tree.column(1, width = 100)
tree.column(2, width = 100)
tree.column(3, width = 100)

scroll = ttk.Scrollbar(frame, orient="vertical", command=tree.yview)
scroll.pack(side = 'right', fill = 'y')

tree.configure(yscrollcommand=scroll.set)

for val in data:
    tree.insert('', 'end', values = (val[0], val[1], val[2]) )

root.mainloop()

答案 1 :(得分:0)

# One way to make a table is to use a loop for the Entry class. 

import tkinter as tk

win=tk.Tk()
win.title('Tk GUI')

cols=['Col1','Col2','Col3']
data = [ ["val1", "val2", "val3"],
         ["asd1", "asd2", "asd3"],
         ["bbb1", "bbb3", "bbb4"],
         ["ccc1", "ccc3", "ccc4"],
         ["ddd1", "ddd3", "ddd4"],
         ["eee1", "eee3", "eee4"] ]
for y in range(len(data)+1):
    for x in range(len(cols)):
        if y==0:
            e=tk.Entry(font=('Consolas 8 bold'),bg='light blue',justify='center')
            e.grid(column=x, row=y)
            e.insert(0,cols[x])
        else:
            e=tk.Entry()
            e.grid(column=x, row=y)
            e.insert(0,data[y-1][x])
win.mainloop()