无法获得Guava 23的SimpleTimeLimiter编译示例

时间:2017-11-22 08:43:54

标签: java guava

我正在关注我在网上多次看到的代码组合including examples here on SO等等,但它不会为我编译。

import com.google.common.util.concurrent.SimpleTimeLimiter;

import java.util.concurrent.Callable;
import java.util.concurrent.TimeUnit;

public class TimeLimit
{
    public static void main(String[] args)
    {
        SimpleTimeLimiter limiter = new SimpleTimeLimiter();
        String result = limiter.callWithTimeout(new Callable<String>()
        {
            public String call()
            {
                return longTimeExecutingMethod();
            }
        }, 3, TimeUnit.SECONDS, false);
    }

    public static String longTimeExecutingMethod()
    {
        return "long time executing method";
    }
}

我得到的错误是:

Error:(10, 45) java: constructor SimpleTimeLimiter in class com.google.common.util.concurrent.SimpleTimeLimiter cannot be applied to given types;
  required: java.util.concurrent.ExecutorService
  found: no arguments
  reason: actual and formal argument lists differ in length

Error:(11, 40) java: method callWithTimeout in class com.google.common.util.concurrent.SimpleTimeLimiter cannot be applied to given types;
  required: java.util.concurrent.Callable<T>,long,java.util.concurrent.TimeUnit
  found: <anonymous java.util.concurrent.Callable<java.lang.String>>,int,java.util.concurrent.TimeUnit,boolean
  reason: cannot infer type-variable(s) T
    (actual and formal argument lists differ in length)

对于我尝试创建单线程执行程序的第一个错误:

SimpleTimeLimiter limiter = new SimpleTimeLimiter(Executors.newSingleThreadExecutor());

但这只会导致第一次编译错误改为:

Error:(10, 45) java: SimpleTimeLimiter(java.util.concurrent.ExecutorService) has private access in com.google.common.util.concurrent.SimpleTimeLimiter

1 个答案:

答案 0 :(得分:2)

使用static factory method

SimpleTimeLimiter limiter = SimpleTimeLimiter.create(executor);