我希望我的按键功能在每次按下都有效,但是setTimeout不能正常工作。这是我的html和脚本;
HTML:
<div id="fake" class="full-height col-md-3 col-sm-12 col-xs-12">
<div class="nav-right">
<div class="form-search">
<input id="fake-search" onkeypress="dialogTrigger(event)" class="fake-search" type="text" />
</div>
</div>
</div>
脚本:
function dialogTrigger(event) {
var keyboardInput = event.which;
keyboardInput = keyboardInput + 5;
var changedInput = String.fromCharCode(keyboardInput);
$("#fake-search").val($("#fake-search").val() + changedInput);
setTimeout(function () {
doSomething(); // about html
}, 10000);
}
答案 0 :(得分:1)
您需要确定逻辑是什么。如果想法是在10秒后将对话框打开一次,那么你需要做这样的事情
var to;
function dialogTrigger(event) {
var keyboardInput = event.which;
keyboardInput = keyboardInput + 5;
var changedInput = String.fromCharCode(keyboardInput);
$("#fake-search").val($("#fake-search").val() + changedInput);
// The line below will only start the timer if none exists;
to = to || setTimeout(function () {
doSomething(); // about html
}, 10000);
}
另一方面,如果您只想在完成输入后打开对话框
var to;
function dialogTrigger(event) {
var keyboardInput = event.which;
keyboardInput = keyboardInput + 5;
var changedInput = String.fromCharCode(keyboardInput);
$("#fake-search").val($("#fake-search").val() + changedInput);
// The line below clear any existing timeout and start a new one
if (to) clearTimeout(to);
to = setTimeout(function () {
doSomething(); // about html
}, 10000);
}
注意10000毫秒约为10秒