我正在开发一个模块,其中管理员会获取已请求批准的候选人列表。目前我正在使用三个选项的单选按钮和一个提交按钮。现在我只想通过选择结果列表的单选按钮来实现它。如何实现此功能以显示同一页面上所有三个不同选择的列表。 这是我创造的,
<form action="" method="POST">
<input type='radio' name='users' value='unapproved' checked /> Unapproved Candidates
<input type='radio' name='users' value='approved' /> Approved Candidates
<input type='radio' id='show' name='users' value='all' /> All Candidates
<input type="submit" value="View Candidates" id="submit" class="btn btn-success"><br><br>
我的mysql查询,
$sqlQuery = "SELECT * FROM tbl_user WHERE type =3 AND status =0";
if(isset($_POST['users'])){
$users=$_POST['users'];
}else{
$users='';
}
switch ($users)
{
case "all":
$sqlQuery = "SELECT * FROM tbl_user WHERE type =3";
break;
case "approved":
$sqlQuery = "SELECT * FROM tbl_user WHERE type =3 AND status =1";
break;
case "unapproved":
$sqlQuery = "SELECT * FROM tbl_user WHERE type =3 AND status =0";
break;
}
我发现这可以通过AJAX实现,但无法找出确切的解决方案。我能否对此有所了解,对我非常有帮助,我们将非常感激。提前致谢
答案 0 :(得分:1)
在每个单选按钮标记上添加一个类,并使用click
事件检查单选按钮的点击和状态。你所要做的就是 -
// Selecting a class using jquery. It will return all the elements that have this class
$(".radioButton").click(function() {
// Using `this`, JS can identify which element has been clicked with class radioButton
// Here I'm checking whether it has been selected or not
if(this).is(":checked") {
// Here I'm fetching the value of selected radio button
var category = $(this).val();
$.ajax({
// Url of your PHP code
url: "YOUR_URL.php",
// Method of your Ajax request
method: "POST",
// Data in case of post request
data: {
'users': category
},
success: function(result){
console.log("Response:\n"+result);
},
error: function(er){
console.log("Error\n"+er);
}
});
}
});