Question

我是来自特定国家/地区的顶级艺术家，该艺术家的专辑以及来自lastfm api的专辑的曲目。我没有错误地获得艺术家和专辑，但是在曲目中它出现了：

for album in album_response['album']['tracks']['track']: KeyError: 'album'

问题似乎是因为一些艺术家的名字中有空格，所以我用＆＃34; +＆＃34;还有＆＃34;％2b＆＃34;但没有解决方案正常工作它总是出现上面的错误。

chosen = artists[i]['name'].replace(" ", "+")
chosen = '+'.join(artists[i]['name'].lower().split())
chosen = artists[i]['name'].replace(" ", "%2B")

轨道部分出错：

tracks = {}
for i,v in albums.items():
    artist = albums[i]['artist'].replace(" ","+")
    name = albums[i]['name'].replace(" ", "+")
    album_response_data = requests.get('http://ws.audioscrobbler.com/2.0/?method=album.getinfo&format=json&api_key='+api_key+'&artist='+artist+'&album='+name)
    album_response = album_response_data.json()

    print(album_response)      
    for album in album_response['album']['tracks']['track']:


        title = album['name']
        number = album['@attr']['rank']
        duration = album['duration']

        tracks[ID] = {}
        tracks[ID]['title'] = title
        tracks[ID]['number'] = number
        tracks[ID]['artist'] = albums[i]['artist']
        tracks[ID]['album'] = albums[i]['name']
        tracks[ID]['albumID'] = albums[i]['ID']
        tracks[ID]['duration'] = duration

        ID += 1

最低工作例子：

import requests

api_key = "b088cbedecd40b35dd89e90f55227ac2"
ID= 0

#Get artists from specific country

artists = {}
for i in range(2, 3):
    artists_response = requests.get(
        'http://ws.audioscrobbler.com/2.0/?method=geo.gettopartists&country=spain&format=json&page=' + str(i) + '&api_key=' + api_key)
    artists_data = artists_response.json()
    for artist in artists_data["topartists"]["artist"]:

        name = artist["name"]

        url = artist["url"]
        #if ID > 3 continue
        artists[ID] = {}
        artists[ID]['ID'] = ID
        artists[ID]['name'] = name

        ID += 1


#Get TopAlbums info from above artists

albums = {}
for i, v in artists.items():
    chosen = artists[i]['name'].replace(" ", "+")
    topalbums_response = requests.get(
        'http://ws.audioscrobbler.com/2.0/?method=artist.gettopalbums&format=json&artist=' + chosen + '&api_key=' + api_key + '&limit=5')
    albums_data = topalbums_response.json()

    for album in albums_data['topalbums']['album']:
        name = album["name"]
        url = album["url"]

        albums[ID] = {}
        albums[ID]['ID'] = ID
        albums[ID]['artist'] = artists[i]['name']
        albums[ID]['artistID'] = artists[i]['ID']
        albums[ID]['name'] = name
        albums[ID]['url'] = url

        ID += 1

#Get tracks info of the above albums

tracks = {}
for i,v in albums.items():
    artist = albums[i]['artist'].replace(" ","+")
    name = albums[i]['name'].replace(" ", "+")
    album_response_data = requests.get('http://ws.audioscrobbler.com/2.0/?method=album.getinfo&format=json&api_key='+api_key+'&artist='+artist+'&album='+name)
    album_response = album_response_data.json()


    for album in album_response['album']['tracks']['track']:  

            title = album['name']

            number = album['@attr']['rank']
            duration = album['duration']

            tracks[ID] = {}

            tracks[ID]['trackID'] = ID

            tracks[ID]['title'] = title
            tracks[ID]['number'] = number
            tracks[ID]['artist'] = albums[i]['artist']
            tracks[ID]['album'] = albums[i]['name']
            tracks[ID]['albumID'] = albums[i]['ID']
            tracks[ID]['duration'] = duration

            ID += 1

Answer 1

问题是，在您收到错误的情况下，album_response是{'error': 6, 'message': 'Album not found', 'links': []}

我添加了一行来打印出在循环中处理的艺术家和专辑的名称，我看到艺术家是Ed Sheeran，但没有相关的专辑。

我不确定为什么会发生这种情况，但我会告诉您需要修复循环变量。在python中，变量在函数范围内，但不在控制结构中。您有嵌套循环，它们都使用i作为循环中的变量。当内循环前进i时，这通常会引起冲突，外循环会看到这些进展。

Answer 2

您的问题在于相册词典中的记录键19：

19：{'ID'：19，'艺术家'：'Ed Sheeran'，'artistID'：3，'image'： 'https://lastfm-img2.akamaized.net/i/u/174s/d08fbb920e514f5c893d95552379d3fc.png'， 'name'：'+'，'url'：'https://www.last.fm/music/Ed+Sheeran/%252B'}

请注意，相册的名称是“+”加号。

您需要将“+”urlencode为％2B 或者用％2B替换“+”。

http://ws.audioscrobbler.com/2.0/?method=album.getinfo&format=json&api_key=b088cbedecd40b35dd89e90f55227ac2&artist=Ed+Sheeran&album=%2B

否则你会回来 'message'：'未找到相册'....

获取每张返回专辑的曲目对某些艺术家不起作用

2 个答案: