Question

考虑一个对象

var obj = {
    val: 123,
    vals: {
        val: 45,
        vals: {
            val: 90
        }
    },
    name: 'abc',
    names: {
        name: 'xyz'
    }
};

我需要这样的东西：

var obj = {
    val: 123,
    vals_val: 45,
    vals_vals_val: 90,
    name: 'abc',
    names_name: 'xyz'
};

有人能告诉我如何进入嵌套对象并访问属性及其值？我尝试了.in循环但没有任何想法。

Answer 1

您可以使用reduce()方法并返回新对象作为结果。

＆＃13;

var obj = {"val":123,"vals":{"val":45,"vals":{"val":90}},"name":"abc","names":{"name":"xyz"}}

function keys(data, prev = '') {
  return Object.keys(data).reduce(function(r, e) {
    var key = prev + (prev.length ? '_' + e : e)
    if (typeof data[e] == 'object') Object.assign(r, keys(data[e], key))
    else r[key] = data[e]
    return r;
  }, {})
}

var r = keys(obj)
console.log(r)

＆＃13;

Answer 2

你可以这样做。我要举一个例子：

var John = {
  age: 23,
  address: {
    Paris: "La rue",
    London: "Tower street"
  },
  surname: "Smith"
};

document.write("Address 1: " + John.address.Paris);
document.write("Surname: " + John.surname);
document.write("Age: " + John.age);

您可以使用“.”

访问每个值

Answer 3

您可以采用递归方式并删除与新密钥不同的项目。

function update(object) {
    function iter(o, p) {
        Object.keys(o).forEach(function (k) {
            var t;
            if (o[k] && typeof o[k] === 'object') {
                iter(o[k], p.concat(k));
            } else {
                t = p.concat(k).join('_');
                object[t] = o[k];
            }
            if (k !== t) {
                delete o[k];
            }
        });
    }
    iter(object, []);
}

var object = { val: 123, vals: { val: 45, vals: { val: 90 } }, name: 'abc', names: { name: 'xyz' } };

update(object);

console.log(object);

查找嵌套对象

3 个答案: