Question

我有这样的数据

df <- structure(list(V1 = structure(c(2L, 4L, 4L, 2L, 4L, 4L, 4L, 4L, 
1L, 1L, 1L, 1L, 3L, 2L, 2L, 4L, NA, 2L, 2L, 2L, 2L, 4L, 5L, 5L, 
5L, NA, NA, 4L), .Label = c("", "1 x Bruit (U)", "1 x TAMAN (M)", 
"2 x Bruit (U)", "2 x TIKIam(T)"), class = "factor"), V2 = structure(c(1L, 
1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 5L), .Label = c("BUX1_T10963", 
"BUX1_T10964", "BUX1_T10965", "BUX1_T10966", "BUX2_T10076"), class = "factor")), .Names = c("V1", 
"V2"), class = "data.frame", row.names = c(NA, -28L))

我试着做一个例子，这样可以帮助我更好

前两列看起来像这样

1 x Bruit（U）BUX1_T10963 2 x Bruit（U）BUX1_T10963 2 x Bruit（U）BUX1_T10963

在这里，我想知道有多少BUX1_T10963有Bruit (U)以及有多少人没有BUX1_T10963 Bruit (U) 5 NA 0 . 0 . 0。或者有其他东西或空单元

例如在上面的示例中，答案是

BUX1_T10963有5个Bruit（U）

输出如下所示

table(df$V1, df$V2)

                BUX1_T10963 BUX1_T10964 BUX1_T10965 BUX1_T10966 BUX2_T10076
                          0           4           0           0           0
  1 x Bruit (U)           1           1           2           4           0
  1 x TAMAN (M)           0           0           1           0           0
  2 x Bruit (U)           2           4           1           1           1
  2 x TIKIam(T)           0           0           0           3           0

@ d.b给出了一个像

这样的答案

table(replace(gsub("(\\d x )", "", df$V1), is.na(df$V1), "NA"), df$V2)

            BUX1_T10963 BUX1_T10964 BUX1_T10965 BUX1_T10966 BUX2_T10076
                      0           4           0           0           0
  Bruit (U)           3           5           3           5           1
  NA                  0           0           1           2           0
  TAMAN (M)           0           0           1           0           0
  TIKIam(T)           0           0           0           3           0


BUX1_T10963 should have 4 empty 
BUX1_T10965 should have 1
BUX1_T10966 should have 2

但是它没有显示像上面这样的格式分配了多少空，也计算了2个不同于1的空白

Dim ystrdycrq As Excel.Workbook
Dim ystrdextr As Excel.Worksheet
Dim ystrdname As String = [String].Format("D:\data\données station\crq{0}.xls", DateTime.Now.AddDays(-1).ToString("ddMMyyyy"))

Dim fichiextreme As String = "K_" & Date.Now.AddDays(-1).ToString("MMdd") & ".xls"
Dim sourcextreme As String = "\\xxxxxxx\aero_mes\piste0\" & fichiextreme
Dim localextreme As String = "D:\data\bdcrq\" & fichiextreme
MsgBox(fichiextreme & sourcextreme & localextreme)

If System.IO.File.Exists(sourcextreme) Then
    File.Copy("\\xxxxxx\aero_mes\piste0\" & fichiextreme, "D:\data\bdcrq\" & fichiextreme, True)
    Dim extrwb As Excel.Workbook
    Dim extrwsh As Excel.Worksheet
    ystrdycrq = app.Workbooks.Open(ystrdname)
    ystrdextr = ystrdycrq.Worksheets("extrèmes")
    extrwb = app.Workbooks.Open(localextreme) ' ne pas oublier de la fermer
    extrwsh = extrwb.Sheets(1)
    extrwsh.Cells(1, 14).Copy(ystrdextr.Cells(1, 1))
    extrwsh.Cells(2, 14).Copy(ystrdextr.Cells(2, 1))
    extrwsh.Cells(1, 15).Copy(ystrdextr.Cells(1, 2))
    extrwsh.Cells(2, 15).Copy(ystrdextr.Cells(2, 2))
    extrwsh.Cells(1, 16).Copy(ystrdextr.Cells(1, 3))
    extrwsh.Cells(2, 16).Copy(ystrdextr.Cells(2, 3))
    extrwsh.Cells(1, 17).Copy(ystrdextr.Cells(1, 4))
    extrwsh.Cells(2, 17).Copy(ystrdextr.Cells(2, 4))
    extrwsh.Cells(1, 54).Copy(ystrdextr.Cells(1, 5))
    extrwsh.Cells(2, 54).Copy(ystrdextr.Cells(2, 5))
    extrwsh.Cells(1, 55).Copy(ystrdextr.Cells(1, 6))
    extrwsh.Cells(2, 55).Copy(ystrdextr.Cells(2, 6))

    txtUmin.Text = ystrdextr.Cells(2, 5).value
    txtHH_Umin.Text = ystrdextr.Cells(2, 6).value
    txtUmax.Text = ystrdextr.Cells(2, 7).value
    txtHH_Umax.Text = ystrdextr.Cells(2, 8).value
    txtTmin.Text = ystrdextr.Cells(2, 1).value
    txtHH_Tmin.Text = ystrdextr.Cells(2, 2).value
    txtTmax.Text = ystrdextr.Cells(2, 3).value
    txtHH_Tmax.Text = ystrdextr.Cells(2, 4).value

    extrwb.Close(SaveChanges:=False)
    ystrdycrq.Close(SaveChanges:=True)
    ystrdextr = Nothing
    ystrdycrq = Nothing
    extrwb = Nothing
    extrwsh = Nothing

    releaseObject(ystrdextr)
    releaseObject(ystrdycrq)
    releaseObject(extrwsh)
    releaseObject(extrwb)
Else
    MsgBox("the file .....", vbOKOnly)

End If

有没有办法让它在同一个原始产品上？

Answer 1

table命令执行您想要的操作：

table(df$V1, df$V2, useNA = "ifany")

表将适用于所有不同的值。如果您希望空白""等同于缺失值NA，则需要对数据进行更改：

df[df == ""] = NA

同样，如果1 x或2 x并不重要，请将其删除。也许添加一个新列

df$goodname = gsub(pattern = "^[0-9]+ x ", replacement = "", x = df$V1)

table(df$goodname, df$V2, useNA = "ifany")
            BUX1_T10963 BUX1_T10964 BUX1_T10965 BUX1_T10966 BUX2_T10076
  Bruit (U)           3           5           3           5           1
  TAMAN (M)           0           0           1           0           0
  TIKIam(T)           0           0           0           3           0
  <NA>                0           4           1           2           0

将数量拉出到自己的列中并制表：

library(stringr)
# extract the number
df$quantity = as.numeric(str_extract(df$V1, "^[0-9]+"))
# any missing values assume to be 1
df$quantity[is.na(df$quantity)] = 1

library(reshape2)
dcast(data = df, formula = goodname ~ V2, value.var = "quantity", fun.aggregate = sum, na.rm = T)
#    goodname BUX1_T10963 BUX1_T10964 BUX1_T10965 BUX1_T10966 BUX2_T10076
# 1 Bruit (U)           5           9           4           6           2
# 2 TAMAN (M)           0           0           1           0           0
# 3 TIKIam(T)           0           0           0           6           0
# 4      <NA>           0           4           1           2           0

如何根据两列计算数字

1 个答案: