Question

我在文本文件中有以下项目，其中包含城市名称和季度收入：

 Atlanta   40 50 23 18
 Denver    56 78 34 11
 Miami     40 34 18 30
 Orlando   55 67 23 11
 Memphis   44 23 56 11
 Boston    55 67 33 23
 Tampa     45 67 54 77

我在列表中对季度收入进行排序时遇到问题。我目前的计划看起来像这样。

with open('revenue.txt', 'r') as f:
text = [line.split() for line in f]
print("{:<12}{:<14}{:>10}{:>9}".format("City", "Revenue", "Total", 
"Average"))
for a in text:
    city = a[0]
    revenue = [int(i) for i in a[1:5]]
    total = sum(revenue)
    avg = sum(revenue)/len(revenue)
    print("{:<12}{}{:>6}{:>9.2f}".format(city, revenue, total, avg))

print("\n""Sort the cities by their Quarter 1 revenues.")

print("\n""Sort the cities by their Quarter 3 revenues.")

print("\n""Sort the cities by their total revenues.")

我试图找出如何对第一季度，第三季度和总列数进行排序，然后打印与其相关的城市。例如：

Sort the cities by their Quarter 1 revenues
['Miami','Atlanta','Memphis','Tampa','Boston','Orlando','Denver']
#  [40,40,44,45,55,55,56]

任何帮助将不胜感激。

Answer 1

我会使用字典和列表来提高排序的可读性以及代码的可用性。我继续并实现了一个打印表格的功能（因为你在你的功能中多次这样做）。我还添加了一个字典列表作为您的新数据集。然后我使用函数sorted来构建新组织的列表。

with open('revenue.txt', 'r') as f:
    def print_table(data):
        for value in data:
            print("{city:<12}{revenue}{total:>6}{avg:>9.2f}".format(**value))
    text = [line.split() for line in f]
    data = []
    for a in text:
        revenue = [int(i) for i in a[1:5]]
        data.append({
            'city': a[0],
            'revenue': revenue,
            'total' : sum(revenue),
            'avg' : sum(revenue)/len(revenue)
        })
    print("\n""Original data set.")
    print_table(data)

    print("\n""Sort the cities by their Quarter 1 revenues.")
    print_table(sorted(data,key=lambda a: a['revenue'][0]))   

    print("\n""Sort the cities by their Quarter 3 revenues.")
    print_table(sorted(data,key=lambda a: a['revenue'][2]))   

    print("\n""Sort the cities by their total revenues.")
    print_table(sorted(data,key=lambda a: a['total']))

Answer 2

您可以使用pandas。这很简单：

import pandas

with open('revenue.txt', 'r') as f:
    text = [line.split() for line in f]

df = pandas.DataFrame(text, columns = ["City", "Revenue", "Total", "Average", "Other"])
df_sorted_by_Total = df.sort_values("Total", ascending=True) # Sort by values of the City column

print(df_sorted_by_Total)
print(df_sorted_by_Total["City"].tolist()) # Print City column as list

输出：

      City Revenue Total Average Other
4  Memphis      44    23      56    11
2    Miami      40    34      18    30
0  Atlanta      40    50      23    18
3  Orlando      55    67      23    11
5   Boston      55    67      33    23
6    Tampa      45    67      54    77
1   Denver      56    78      34    11
['Memphis', 'Miami', 'Atlanta', 'Orlando', 'Boston', 'Tampa', 'Denver']

Answer 3

你可以这样排序：

text = [ 
["Atlanta", 40,50,23,18 ],
["Denver ", 56,78,34,11 ],
["Miami  ", 40,34,18,30 ],
["Orlando", 55,67,23,11 ],
["Memphis", 44,23,56,11 ],
["Boston ", 55,67,33,23 ],
["Tampa  ", 45,67,54,77 ]]


for a in text:
    city = a[0]
    revenue = [int(i) for i in a[1:5]]
    total = sum(revenue)
    avg = sum(revenue)/len(revenue)
  #  print("{:<12}{}{:>6}{:>9.2f}{:>9.2f}{:>9.2f}".format(city, revenue, total, avg))
    a.append(total) # append it to your former array
    a.append(avg)   # append it to your former array


print ("1.Q")
printIt(sorted(text, key=lambda x: x[1])) # sort by 1. Quarter number
print ("2.Q")
printIt(sorted(text, key=lambda x: x[2])) # sort by 2. Quarter number
print ("3.Q")
printIt(sorted(text, key=lambda x: x[3])) # etc.
print ("4.Q")
printIt(sorted(text, key=lambda x: x[4]))
print ("Total")
printIt(sorted(text, key=lambda x: x[5]))
print ("Avg")
printIt(sorted(text, key=lambda x: x[6]))

sorted(..)将创建一个新的列表对象 - 您可以将其简单地存储到您想要使用的内容中 - 出于演示目的，只需简单地打印它们即可。

输出：

1.Q
[ ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
  ['Miami  ', 40, 34, 18, 30, 122, 30.5],
  ['Memphis', 44, 23, 56, 11, 134, 33.5], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0], 
  ['Boston ', 55, 67, 33, 23, 178, 44.5], 
  ['Denver ', 56, 78, 34, 11, 179, 44.75]]

2.Q
[ ['Memphis', 44, 23, 56, 11, 134, 33.5], 
  ['Miami  ', 40, 34, 18, 30, 122, 30.5],
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
  ['Orlando', 55, 67, 23, 11, 156, 39.0], 
  ['Boston ', 55, 67, 33, 23, 178, 44.5], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75], 
  ['Denver ', 56, 78, 34, 11, 179, 44.75]]

3.Q
[ ['Miami  ', 40, 34, 18, 30, 122, 30.5],
  ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0], 
  ['Boston ', 55, 67, 33, 23, 178, 44.5], 
  ['Denver ', 56, 78, 34, 11, 179, 44.75],
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75], 
  ['Memphis', 44, 23, 56, 11, 134, 33.5]]

4.Q
[ ['Denver ', 56, 78, 34, 11, 179, 44.75], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0],
  ['Memphis', 44, 23, 56, 11, 134, 33.5],
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
  ['Boston ', 55, 67, 33, 23, 178, 44.5],
  ['Miami  ', 40, 34, 18, 30, 122, 30.5], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75]]

Total
[ ['Miami  ', 40, 34, 18, 30, 122, 30.5], 
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
 ['Memphis', 44, 23, 56, 11, 134, 33.5], 
  ['Orlando', 55, 67, 23, 11, 156, 39.0],
  ['Boston ', 55, 67, 33, 23, 178, 44.5],
  ['Denver ', 56, 78, 34, 11, 179, 44.75], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75]]

Avg
[ ['Miami  ', 40, 34, 18, 30, 122, 30.5], 
  ['Atlanta', 40, 50, 23, 18, 131, 32.75],
  ['Memphis', 44, 23, 56, 11, 134, 33.5],
  ['Orlando', 55, 67, 23, 11, 156, 39.0],
  ['Boston ', 55, 67, 33, 23, 178, 44.5],
  ['Denver ', 56, 78, 34, 11, 179, 44.75], 
  ['Tampa  ', 45, 67, 54, 77, 243, 60.75]]

这适用于How to sort a list of objects based on an attribute of the objects?中显示的问题。已标记的问题为重复。

如何在python

3 个答案: