Question

所以我有一个简单的程序，它将常用密码列表中的所有值哈希，然后将哈希值与给定的哈希值进行比较。然后破解密码。

然而它似乎不起作用，因为passwd_found仍然是假的，我相信它的IF语句不起作用。任何帮助表示赞赏。

dic = []

passwd_hash = '4297f44b13955235245b2497399d7a93'
passwd_found = False

for k in dic:
    md5hash = hashlib.md5(k.encode('utf-8'))
    print(md5hash.hexdigest())

if passwd_hash in md5hash:
    passwd_found = True
else:
    passwd_found = False

Answer 1

我相信你的缩进已经关闭，你需要在比较中使用.hexdigest()，否则你会收到错误：

TypeError：类型＆＃39; _hashlib.HASH＆＃39;的参数是不可迭代的

import hashlib

dic = ['123','1234','12345','123456','1234567','12345678','password', 'qwerty','abc','abcd','abc123','111111','monkey','arsenal','letmein','trustno1','dragon','baseball','superman','iloveyou','starwars','montypython','cheese','123123','football','batman']

passwd_hash = '4297f44b13955235245b2497399d7a93'
passwd_found = False

for k in dic:
    md5hash = hashlib.md5(k.encode('utf-8'))
    t_hash = md5hash.hexdigest()
    print(t_hash)

    if passwd_hash in t_hash:
        passwd_found = True
    else:
        passwd_found = False

    if passwd_found:
        print(k) # 123123 matches

散列列表并在Python中进行比较

1 个答案: