Question

我想要进行插入选择，但在phpmyadmin中我一直收到错误＃1292 - 日期值不正确：＆＃39;＆＃39;对于列＆＃39;日期＆＃39;在第1行现在，选择对它有效，没有错误。我只在添加INSERT语句时才会收到错误，例如这可以

SELECT
    `SalesInvoice_id`,
    `Date`,
    IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount`
    FROM
    (SELECT 
        `salesinvoice`.`SalesInvoice_id`,
         `DatePaid` AS `Date`,
        ROUND(SUM((`Unit_Cost`*`Quantity`)),2) as `valueOriginal`,
        IF(`salesinvoice`.`VAT`=2,ROUND(SUM(((`Unit_Cost`)*`Quantity`)/100*`salesinvoice_products`.`VAT`),2),0) as `VATOriginal`,
         `InvoiceType`
        FROM `salesinvoice`
        LEFT JOIN `salesinvoice_products` ON `salesinvoice`.`SalesInvoice_id` = `salesinvoice_products`.`SalesInvoice_id`
          GROUP BY `salesinvoice`.`SalesInvoice_id`
    ) a
 WHERE `InvoiceType`!='3' && `Date`!=''

但是当我这样做时

INSERT INTO `salesinvoice_payments` (`SalesInvoice_id`,`Date`,`Amount`)
SELECT
    `SalesInvoice_id`,
    `Date`,
    IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount`
    FROM
    (SELECT 
        `salesinvoice`.`SalesInvoice_id`,
         `DatePaid` AS `Date`,
        ROUND(SUM((`Unit_Cost`*`Quantity`)),2) as `valueOriginal`,
        IF(`salesinvoice`.`VAT`=2,ROUND(SUM(((`Unit_Cost`)*`Quantity`)/100*`salesinvoice_products`.`VAT`),2),0) as `VATOriginal`,
         `InvoiceType`
        FROM `salesinvoice`
        LEFT JOIN `salesinvoice_products` ON `salesinvoice`.`SalesInvoice_id` = `salesinvoice_products`.`SalesInvoice_id`
          GROUP BY `salesinvoice`.`SalesInvoice_id`
    ) a
 WHERE `InvoiceType`!='3' && `Date`!=''

我收到错误。好的这是我的架构

DROP TABLE IF EXISTS salesinvoice_payments;
DROP TABLE IF EXISTS salesinvoice;
DROP TABLE IF EXISTS salesinvoice_products;

CREATE TABLE salesinvoice_payments
    (`sipID` int(11) NOT NULL AUTO_INCREMENT,
    `salesinvoice_id` int,
    `Date` date,
    `Amount` int,
     PRIMARY KEY (`sipID`))
;

CREATE TABLE salesinvoice (
  `SalesInvoice_id` int(11) NOT NULL AUTO_INCREMENT,
  `VAT` tinyint(1) DEFAULT NULL,
  `DatePaid` date DEFAULT NULL,
  `InvoiceType` tinyint(1) DEFAULT 1,
  PRIMARY KEY (`SalesInvoice_id`)
);

 CREATE TABLE salesinvoice_products (
  product_ID int(11) NOT NULL AUTO_INCREMENT,
  SalesInvoice_id int(11) DEFAULT NULL,
  Description varchar(255) DEFAULT NULL,
  Unit_Cost decimal(19, 2) DEFAULT NULL,
  Quantity int(11) DEFAULT NULL,
  VAT decimal(10, 1) DEFAULT NULL,
  PRIMARY KEY (product_ID)
);

INSERT INTO `salesinvoice`
    (`SalesInvoice_id`,`VAT`, `DatePaid`, `InvoiceType`)
VALUES
    (1,2,'2017-11-07',1),
    (2,2,'2017-11-07',1),
    (3,2,'2017-11-07',1),
    (4,2,'2017-11-07',1),
    (5,2,'2017-11-07',1),
    (6,2,'2017-11-07',1)
;

INSERT INTO `salesinvoice_products`
    (`SalesInvoice_id`, `Description`, `Unit_Cost`,`Quantity`,`VAT`)
VALUES
    (3,'Sausage',1.50,5,21),
    (3,'Cabbage',2.50,15,21),
    (4,'Herring',2.50,15,21),
    (4,'Red',2.50,15,21),
    (3,'Dongle',2.50,15,21),
    (2,'Thingy',2.50,15,21),
    (2,'Spaceship',2.50,15,21),
    (1,'Car',2.50,15,21),
    (1,'Alien',2.50,15,21)
;

INSERT INTO `salesinvoice_payments` (`SalesInvoice_id`,`Date`,`Amount`)
SELECT
    `SalesInvoice_id`,
    `Date`,
    IFNULL(`valueOriginal`+`VATOriginal`,0) as `Amount`
    FROM
    (SELECT 
        `salesinvoice`.`SalesInvoice_id`,
         `DatePaid` AS `Date`,
        ROUND(SUM((`Unit_Cost`*`Quantity`)),2) as `valueOriginal`,
        IF(`salesinvoice`.`VAT`=2,ROUND(SUM(((`Unit_Cost`)*`Quantity`)/100*`salesinvoice_products`.`VAT`),2),0) as `VATOriginal`,
         `InvoiceType`
        FROM `salesinvoice`
        LEFT JOIN `salesinvoice_products` ON `salesinvoice`.`SalesInvoice_id` = `salesinvoice_products`.`SalesInvoice_id`
          GROUP BY `salesinvoice`.`SalesInvoice_id`
    ) a
 WHERE `InvoiceType`!='3' && `Date`!=''

好的，第一次发布堆栈溢出时，我将展示我的sqlfiddle。 select插入在sqlfiddle中工作正常，但不在phpmyadmin中。但是在phpmyadmin中我收到错误＃1292 - 日期值不正确：＆＃39;＆＃39;对于列＆＃39;日期＆＃39;在第1行。 SQLFIDDLE

由于某种原因，日期没有正确发送。

Answer 1

SELECT时会收到相同的警告。

mysql> SELECT ... WHERE `InvoiceType`!='3' && `Date`!='';
+-----------------+------------+--------+
| SalesInvoice_id | Date       | Amount |
+-----------------+------------+--------+
|               1 | 2017-11-07 |  90.75 |
|               2 | 2017-11-07 |  90.75 |
|               3 | 2017-11-07 |  99.83 |
|               4 | 2017-11-07 |  90.75 |
|               5 | 2017-11-07 |   0.00 |
|               6 | 2017-11-07 |   0.00 |
+-----------------+------------+--------+
6 rows in set, 1 warning (0.01 sec)

mysql> show warnings;
+---------+------+-----------------------------------------------------+
| Level   | Code | Message                                             |
+---------+------+-----------------------------------------------------+
| Warning | 1292 | Incorrect date value: '' for column 'Date' at row 1 |
+---------+------+-----------------------------------------------------+

当我们放弃这种情况时，没有任何警告。

mysql> SELECT ... WHERE `InvoiceType`!='3';
+-----------------+------------+--------+
| SalesInvoice_id | Date       | Amount |
+-----------------+------------+--------+
|               1 | 2017-11-07 |  90.75 |
|               2 | 2017-11-07 |  90.75 |
|               3 | 2017-11-07 |  99.83 |
|               4 | 2017-11-07 |  90.75 |
|               5 | 2017-11-07 |   0.00 |
|               6 | 2017-11-07 |   0.00 |
+-----------------+------------+--------+
6 rows in set (0.01 sec)

所以它抱怨将日期列与''进行比较，而不是将值插入表格。

将MySQL日期与''进行比较是没有意义的。具有DATE或DATETIME类型的列不能为空字符串。无效日期转换为0000-00-00，或者如果您使用严格模式，则它们是错误的。您永远不能获得''的日期列。

您可以获取NULL的日期列。这可能是你试图测试的。 NULL和空字符串''在标准SQL和MySQL中是不同的。

我猜你有Oracle经验，其中NULL和空字符串在许多上下文中都被视为相同（Oracle的这种行为不是标准SQL）。

如果您要过滤掉IS NOT NULL，我建议您使用NULL。

mysql> SELECT ... WHERE `InvoiceType`!='3' AND `Date` IS NOT NULL;
+-----------------+------------+--------+
| SalesInvoice_id | Date       | Amount |
+-----------------+------------+--------+
|               1 | 2017-11-07 |  90.75 |
|               2 | 2017-11-07 |  90.75 |
|               3 | 2017-11-07 |  99.83 |
|               4 | 2017-11-07 |  90.75 |
|               5 | 2017-11-07 |   0.00 |
|               6 | 2017-11-07 |   0.00 |
+-----------------+------------+--------+
6 rows in set (0.01 sec)

我在插入选择上获得了不正确的日期值

1 个答案: