Question

我有Spring + JPA（Hibernate）项目，我连接到 MsSQL 数据库，现在我需要打开一个新连接，但这次它将是 MySQL 。我正在使用XML配置

<bean id="hibernateJpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />

<bean id="dataSource" class="org.apache.commons.dbcp2.BasicDataSource"
    destroy-method="close">
    <property name="driverClassName" value="${spring.datasource.driverClassName}" />
   ....
</bean>

<bean id="entityManagerFactory"
    class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
    p:dataSource-ref="dataSource" p:packagesToScan="com.wsg.admin.api.model"
    p:jpaVendorAdapter-ref="hibernateJpaVendorAdapter">

    <property name="jpaProperties">
        <props>
            <prop key="hibernate.cache.use_second_level_cache">false</prop>
            ....
        </props>
    </property>
</bean>

<tx:annotation-driven transaction-manager="transactionManager" />

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>

<!-- Configure the MySQL connection -->
<bean id="enduserDataSource" class="org.apache.commons.dbcp2.BasicDataSource"
    destroy-method="close">
    <property name="driverClassName" value="${enduser.db.driver}" />
    ....
</bean>

<bean id="enduserEntityManagerFactory"
    class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
    p:dataSource-ref="enduserDataSource" p:packagesToScan="com.wsg.admin.api.model"
    p:jpaVendorAdapter-ref="hibernateJpaVendorAdapter">

    <property name="jpaProperties">
        <props>
            <prop key="hibernate.cache.use_second_level_cache">false</prop>
            ....
        </props>
    </property>
</bean>

<tx:annotation-driven transaction-manager="enduserTransactionManager" />

<bean id="enduserTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="enduserEntityManagerFactory" />
</bean>

然后我尝试使用片段

注入entityManager

@Autowired
EntityManager entityManager;

但我得到例外

Caused by: org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'brandServiceImpl': Unsatisfied dependency expressed through field 'entityManager'; nested exception is org.springframework.beans.factory.NoUniqueBeanDefinitionException: No qualifying bean of type 'javax.persistence.EntityManager' available: expected single matching bean but found 2: org.springframework.orm.jpa.SharedEntityManagerCreator#0,org.springframework.orm.jpa.SharedEntityManagerCreator#1

Answer 1

由于您有两个实体管理器（来自EntityMangaerFactory），您需要告诉spring您要成为Autowired的特定实体管理器。使用@Qualifier

@Autowired  
@Qualifier("enduserEntityManagerFactory")  // use bean id of the Entity Manager Factory you want to inject
EntityManagerFactory entityManagerFactory

EntityManager entityManager = entityManagerFactory.createEntityManager();

有关此here

的更多信息

Answer 2

固定。感谢@Volceri 我使用了答案https://stackoverflow.com/a/18073628/1973933，如下所示

为<property name="persistenceUnitName" value="appPU" />

中的每一个添加entityManagerFactory

<bean id="entityManagerFactory" ...  >

    <property name="jpaProperties">
        <props>
            <prop key="hibernate.cache.use_second_level_cache">false</prop>
            ...
        </props>
    </property>
    <property name="persistenceUnitName" value="dataSourcePU" />
</bean>

<bean id="endUserEntityManagerFactory" ...  >

    <property name="jpaProperties">
        <props>
            <prop key="hibernate.cache.use_second_level_cache">false</prop>
            ...
        </props>
    </property>
    <property name="persistenceUnitName" value="enduserDataSourcePU" />
</bean>

并注入em对象，我使用

@PersistenceContext(unitName="dataSourcePU")
EntityManager entityManager;

@PersistenceContext(unitName="enduserDataSourcePU")
EntityManager endUserEntityManager;

在spring应用程序中注入2（在不久的将来3个）不同的entityManagerFactory（或entityManager）

2 个答案: