来自SpringFramework @Controller，@ ResponseBody的JSON名称

Question

我有一个简单的Spring Controller，其目的是返回我的实体对象的RESTful JSON响应。它以与我的实体匹配的标准camelCase名称返回数据。但是，我希望JSON名称与数据库字段匹配，这只是TitleCase。有一个简单的方法吗？下面是Controller和JSON返回的示例。

@Controller
@RequestMapping(path="/Users")
public class UserController {
    @Autowired
    private UserRepository userRepository;

    @GetMapping(path="/List")
    public @ResponseBody Iterable<User> getAllUsers() {
            // This returns a JSON or XML with the users
            return userRepository.findAll();
        }
    }

结果JSON：

{"id":1,"userName":"SYSTEM","password":"xxxxx","firstName":"System","lastName":"System","phone":"XXX-XXX-XXXX","email":"system@test.com","reviewer":false,"admin":false}

这是我的用户实体类：

package com.prs.business;


import java.io.Serializable;
import java.sql.Timestamp;
import java.time.LocalDateTime;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;

import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonProperty;

@Entity
public class User implements Serializable {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private int id;
    @Column(name="username")
    @JsonProperty("UserName")
    private String userName;
    private String password;
    @Column(name="firstname")
    private String firstName;
    @Column(name="lastname")
    private String lastName;
    private String phone;
    private String email;
    @Column(name="isreviewer")
    private boolean reviewer;
    @Column(name="isadmin")
    private boolean admin;
    @Column(name="isactive")
    private boolean active;
    @Column(name="datecreated")
    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSS")
    private Timestamp dateCreated;

    public User() {
        userName = "";
        password = "";

    }

    public User(int id, String userName, String password, String firstName, String lastName, String phoneNumber,
            String email, boolean reviewer, boolean admin) {
        super();
        this.id = id;
        this.userName = userName;
        this.password = password;
        this.firstName = firstName;
        this.lastName = lastName;
        this.phone = phoneNumber;
        this.email = email;
        this.reviewer = reviewer;
        this.admin = admin;
    }

    public User(String un, String pw, String fn, String ln, String pn, String e, boolean m, boolean a) {
        setUserName(un);
        setPassword(pw);
        setFirstName(fn);
        setLastName(ln);
        setPhoneNumber(pn);
        setEmail(e);
        setReviewer(m);
        setAdmin(a);
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getUserName() {
        return userName;
    }
    public void setUserName(String userName) {
        this.userName = userName;
    }
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
    public String getFirstName() {
        return firstName;
    }
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }
    public String getLastName() {
        return lastName;
    }
    public void setLastName(String lastName) {
        this.lastName = lastName;
    }
    public String getPhone() {
        return phone;
    }
    public void setPhoneNumber(String phoneNumber) {
        this.phone = phoneNumber;
    }
    public String getEmail() {
        return email;
    }
    public void setEmail(String email) {
        this.email = email;
    }
    public boolean isReviewer() {
        return reviewer;
    }
    public void setReviewer(boolean inReviewer) {
        this.reviewer = inReviewer;
    }
    public boolean isAdmin() {
        return admin;
    }
    public void setAdmin(boolean inAdmin) {
        this.admin = inAdmin;
    }
    public boolean isActive() {
        return admin;
    }
    public void setActive(boolean inActive) {
        this.admin = inActive;
    }

    public Timestamp getDateCreated() {
        return dateCreated;
    }

    public void setDateCreated(Timestamp dateCreated) {
        this.dateCreated = dateCreated;
    }

    @Override
    public String toString() {
        return "User [id=" + id + ", userName=" + userName + ", password=" + password + ", firstName=" + firstName
                + ", lastName=" + lastName + ", phoneNumber=" + phone + ", email=" + email + ", reviewer="
                + reviewer + ", admin=" + admin + "]";
    }

}

Answer 1

userRepository.findAll（）可能会返回一个POJO，对吗？ 在那个pojo中，在getter之前或字段声明之前，你可以添加一个像

这样的注释

@JsonProperty("<hereYouWriteTheNameYouPrefer>")
private String userName;

或

private String userName;

@JsonProperty("<hereYouWriteTheNameYouPrefer>")
public String getUserName(){
    return userName;
}

Answer 2

如何为所有JSON属性名启用pascal case？

在application.properties

中添加以下设置

spring.jackson.property-naming-strategy=UPPER_CAMEL_CASE