Question

我想总和秒的总和，如答案是total_seconds 49058，而billable是540，它可以通过计费，我已经尝试了下面提到的mysql查询。

ID   billable total_seconds
----------------------------
9326      480          2254
9352       60          3657
9352       60          2756
9352       60            14
9326      480          2607
9326      480           122
9326      480           162
9326      480           559
9326      480          2478
9326      480           313
9326      480           234
9326      480           548
9326      480          2400
9326      480           564
9326      480          4449
9326      480         12986
9326      480         12942
9326      480            13

查询：

SELECT DISTINCT 
    sub.user_id,
    e.name, e.employee_id,
    sub.id, sub.billable,
    history.total_seconds
FROM 
    v_wa_tasks as t
JOIN 
    v_wa_sub_tasks as sub ON t.id = sub.task_id 
JOIN 
    v_wa_task_histories as history ON sub.id = history.sub_task_id
JOIN 
    v_employees as e ON sub.user_id = e.id  
WHERE 
    e.id = 18 
    AND t.status_id = 5 
    AND t.status_id != 9 
    AND t.task_nature_id != 4  
    AND sub.review_type = 0 
    AND t.start_time BETWEEN "2017-10-05 00:00:00" AND "2017-10-05 23:59:00"

Answer 1

select distinct和sum很少能很好地协同工作。几乎总是你需要做更多的工作作为子查询，不仅要获得正确的总和，还要减少行数。以下是对历史求和的可能方法：

SELECT
      sub.user_id
    , e.NAME
    , e.employee_id
    , sub.id
    , sub.billable
    , history.total_seconds
FROM v_wa_tasks AS t
INNER JOIN v_wa_sub_tasks AS sub ON t.id = sub.task_id
INNER JOIN (
      SELECT
            sub_task_id
          , SUM(total_seconds) total_seconds
      FROM v_wa_task_histories
      GROUP BY
            sub_task_id
) AS history ON sub.id = history.sub_task_id
INNER JOIN v_employees AS e ON sub.user_id = e.id
WHERE e.id = 18
AND t.status_id = 5
AND t.status_id != 9
AND t.task_nature_id != 4
AND sub.review_type = 0
AND t.start_time >= '2017-10-05' AND t.start_time < '2017-10-06'

NB ：'23：59：59'不一天结束，使用它可能会让你有一天陷入困境（MySQL现在支持sub - 第二次精确度）。最好的解决方案是在日期范围内避免“介于”之间。请改用>=和<，但请注意您将更高的日期“推高”到第二天。见Bad habits to kick : mis-handling date / range queries

在MySql GROUP BY和SUM（）中进行相同的Mysql查询

1 个答案: