//Program to find max occurring character in string
#include<stdio.h>
#include<conio.h>
#define MAX_SIZE 100 // Maximum string size, change to make string smaller or larger
#define MAX_CHARS 255 // Maximum characters allowed for characters
void main()
{
char str[MAX_SIZE]; //store the string
int freq[MAX_CHARS]; // store frequency of each character
int i, max; // i is for loop max to store frequency
int ascii; //stores ascii value convertd from each char
char ch; //for choice
do{
clrscr();
i=0;
printf("\nEnter any string: ");
gets(str);
// Initializes frequency of all characters to 0
for(i=0; i<MAX_CHARS; i++)
{
freq[i] = 0;
}
// Finds occurance/frequency of each characters
i=0;
while(str[i] != '\0')
{
ascii = (int)str[i];
freq[ascii] += 1; //string's element is casted to int to store its ascii value for further comparision
i++;
}
// Finds maximum frequency of character
max = 0;
for(i=0; i<MAX_CHARS; i++)
{
if(freq[i] > freq[max])
max = i; //to print no. of times
}
printf("\nMaximum occurring character is '%c' = %d times.", max, freq[max]);
printf("\n Want to find again??(y/n):");
scanf("%c",&ch);
}while(ch=='Y'||ch=='y');
}
当我给它输入:&#34; aaaaeeee&#34;时,输出是&#34; a&#34;发生了4次,但是&#34; e&#34;也发生了4次。我知道这是按ascii值排序的,这就是为什么它给出了&#34; a&#34;作为输出,但是我可以在这个程序中做什么,输出给出了&#34; a&#34;和&#34; e&#34;当这种情况发生时作为输出?
答案 0 :(得分:2)
提前添加最大计算
i = 0;
max = 0;
while(str[i] != '\0')
{
ascii = (int)str[i];
freq[ascii] += 1;
if (freq[ascii] > max) max = freq[ascii]; // <==== here
i++;
}
请注意,这是您可能拥有的相同角色的最大数量。
然后显示最大值等于max
的所有字符for(i=0; i<MAX_CHARS; i++)
{
if(freq[i] == max) printf("Character %c is at max %d\n", i, max);
}
在while
添加char c ; while ((c = getchar()) != EOF && c != '\n');
scanf("%c",&ch);
char c;
while ((c = getchar()) != EOF && c != '\n'); // <== note the ';'
} while(ch=='Y'||ch=='y');
请注意,您不应使用gets
,reason is explained here。
整个代码:
void main()
{
char str[MAX_SIZE]; //store the string
int freq[MAX_CHARS]; // store frequency of each character
int i, max; // i is for loop max to store frequency
int ascii; //stores ascii value convertd from each char
char ch; //for choice
do {
printf("\nEnter any string: ");
gets(str);
// Initializes frequency of all characters to 0
for(i=0; i<MAX_CHARS; i++)
{
freq[i] = 0;
}
// Finds occurance/frequency of each characters
for(i=0,max=0 ; str[i] != '\0' ; i++)
{
ascii = (int)str[i];
freq[ascii] += 1; //string's element is casted to int to store its ascii value for further comparision
if (freq[ascii] > max) max = freq[ascii];
}
for(i=0; i<MAX_CHARS; i++)
{
if(freq[i] == max) printf("Character %c is at max %d\n", i, max);
}
printf("\n Want to find again??(y/n):");
scanf("%c",&ch);
char c;
while ((c = getchar()) != EOF && c != '\n');
}while(ch=='Y'||ch=='y');
}
答案 1 :(得分:1)
在这一行之上
printf("\nMaximum occurring character is '%c' = %d times.", max, freq[max]);
删除它并添加此代码
for(i=0;i<MAX_CHARS;i++)
{
if(freq[i]==freq[max])
{
printf("\nMaximum occurring character is '%c' = %d times.", i, freq[i]);
}
}