Question

我有一个我在django处理的表单。它正在正确处理表单，但在处理完成后，它会抛出一个无法发生的http响应错误......

这是表格：

# create a new expense form - group
class CreateExpenseForm(forms.ModelForm):
    split_choices = (('1', 'even'),
                      ('2', 'individual'))
    split = forms.TypedChoiceField(
        choices=split_choices
    )
    class Meta:
        model = Expense
        fields = ['location', 'description', 'amount', 'split']

这是视图：我将打破错误发生的地方：

    if request.method == 'POST':
        form = CreateExpenseForm(request.POST)
        if form.is_valid():
            cd = form.cleaned_data
            location = cd['location']
            description = cd['description']
            amount = cd['amount']
            split = cd['split']
            reference = generate_number()
            for member in members:
                if member.user.username in request.POST:
                    new_expense = Expense.objects.create(
                        user = member.user,
                        group = group,
                        location = location,
                        description = description,
                        amount = amount,
                        reference = reference,
                        created_by = user,
                    )
            print('all exepense accounted for')

所有费用占＆＃39;在终端打印然后它抛出错误

现在使用表单，只有两个选项可以分为1和2

我正在选择选项1（偶数），因此拆分应为1，但没有打印消息显示...

            if split == 1:
                print('even split')
                print(groupid)
                print(groupname)
                return redirect('even_expense', groupid = groupid, groupname = groupname)
            if split == 2:
                print('individual splut')
                return redirect('test')

它不会打印任何错误，因此必须在上面的部分中发生http响应错误。

        else:
            print(form.errors)
            return redirect('test')
    else:
        form = CreateExpenseForm()
        parameters = {
            'form':form,
            'members':members,
        }
        return render(request, 'groups/create_expense.html', parameters)

Answer 1

请试试这个：

field = forms.TypedChoiceField(choices=CHOICES, coerce=int)

添加 coerce = int 会将值转换为您想要的类型，此处类型为 int 。

获取django中不可能发生的http响应

1 个答案: