我一直在寻找一种在Swift 4中使用Timer的方法,并查看了this文章。我在xcode中测试了我的代码,当计时器第一次打勾时(在这种情况下10秒后)应用程序崩溃,我收到错误,虽然构建成功。
2017-11-20 19:54:42.781502-0700 Rock Prodigy[3022:554505] -[_SwiftValue tick]: unrecognized selector sent to instance 0x608000051520
2017-11-20 19:54:42.791278-0700 Rock Prodigy[3022:554505] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[_SwiftValue tick]: unrecognized selector sent to instance 0x608000051520'
*** First throw call stack:
(
0 CoreFoundation 0x000000010360d1ab __exceptionPreprocess + 171
1 libobjc.A.dylib 0x0000000102ca2f41 objc_exception_throw + 48
2 CoreFoundation 0x000000010368da34 -[NSObject(NSObject) doesNotRecognizeSelector:] + 132
3 CoreFoundation 0x00000001035900a8 ___forwarding___ + 1432
4 CoreFoundation 0x000000010358fa88 _CF_forwarding_prep_0 + 120
5 Foundation 0x000000010270e1ee __NSFireTimer + 83
6 CoreFoundation 0x000000010359d2a4 __CFRUNLOOP_IS_CALLING_OUT_TO_A_TIMER_CALLBACK_FUNCTION__ + 20
7 CoreFoundation 0x000000010359cf62 __CFRunLoopDoTimer + 1026
8 CoreFoundation 0x000000010359cb1a __CFRunLoopDoTimers + 266
9 CoreFoundation 0x0000000103594534 __CFRunLoopRun + 2308
10 CoreFoundation 0x00000001035939b9 CFRunLoopRunSpecific + 409
11 GraphicsServices 0x00000001090e29c6 GSEventRunModal + 62
12 UIKit 0x0000000103a885e8 UIApplicationMain + 159
13 Rock Prodigy 0x000000010238b637 main + 55
14 libdyld.dylib 0x0000000107aa1d81 start + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException
(lldb)
这是我的快速4代码
import UIKit
class GeneralFitness: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
}
var timer: Timer! = Timer.scheduledTimer(timeInterval: 10, target: self, selector: #selector(tick), userInfo: nil, repeats: true)
@objc func tick() {
print("tick")
}
}
如果您有任何问题,请与我们联系。
答案 0 :(得分:6)
您的计时器以错误的方式初始化,因为:
如果使用闭包来初始化属性,请记住在执行闭包时尚未初始化实例的其余部分。这意味着您无法从闭包中访问任何其他属性值,即使这些属性具有默认值也是如此。
此外:
您也不能使用隐式自身属性,也不能调用任何实例的方法(参见here)
因此,要解决您的问题,您应该在viewDidLoad
内移动此类代码。所以你可以试试这个:
import UIKit
class ViewController: UIViewController {
weak var timer: Timer?
override func viewDidLoad() {
super.viewDidLoad()
Timer.scheduledTimer(withTimeInterval: 10, repeats: true, block: { [weak self] timer in
self?.timer = timer
self?.tick()
})
}
deinit {
self.timer?.invalidate()
}
@objc func tick() {
print("tick")
}
}
答案 1 :(得分:6)
作为Andrea said,您应该在viewDidLoad
中实例化计时器。另外the documentation says:
选择器应具有以下签名:
timerFireMethod:
(包括冒号以指示该方法接受参数)。
并且不要忘记在viewDidDisappear
中禁用此计时器。您无法在invalidate
中deinit
,因为重复计时器会保留对其目标的强引用,只要计时器正在运行,您的deinit
就不会被调用。如果您在viewDidDisappear
中将其删除,则可能需要在viewDidAppear
中创建计时器。
因此,导致类似:
class ViewController: UIViewController {
weak var timer: Timer?
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear(animated)
timer = Timer.scheduledTimer(timeInterval: 10, target: self, selector: #selector(tick(_:)), userInfo: nil, repeats: true)
}
override func viewDidDisappear(_ animated: Bool) {
super.viewDidDisappear(animated)
timer?.invalidate()
}
@objc func tick(_ timer: Timer) {
print("tick")
}
}
或者你可以使用带有[weak self]
模式的基于块的再现,并且计时器不会保持对视图控制器的强引用,在这种情况下你可以使用deinit
:
class ViewController: UIViewController {
var timer: Timer?
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear(animated)
timer = Timer.scheduledTimer(withTimeInterval: 10, repeats: true) { [weak self] timer in // the `[weak self] reference is only needed if you reference `self` in the closure
print("tick")
}
}
deinit {
timer?.invalidate()
}
}
答案 2 :(得分:0)
在swift 4中试试这个
import UIKit
class ViewController: UIViewController {
var timer: Timer!
override func viewDidLoad() {
super.viewDidLoad()
self.timer = Timer.scheduledTimer(timeInterval: 10, target: self, selector: #selector(self.updateValue), userInfo: nil, repeats: true)
}
func updateValue(){
print("Timer is call")
}
}