Question

我想在循环期间为追加 numpy数组创建两个二进制文件到每个文件中。我编写了以下方法（我使用Python 2.7）：

for _ in range(5):
    C = np.random.rand(1, 5)
    r = np.random.rand(1, 5)
    with open("C.bin", "ab") as file1, open("r.bin", "ab") as file2:
        # Append to binary files
        np.array(C).tofile(file1)
        np.array(r).tofile(file2)

# Now printing to check if appending is successful
C = np.load("C.bin")
r = np.load("r.bin")
print (C)
print (r)

但是，我一直收到这个错误：

Traceback (most recent call last):
  File "test.py", line 15, in <module>
    C = np.load("C.bin")
  File "/anaconda/lib/python2.7/site-packages/numpy/lib/npyio.py", line 429, in load
    "Failed to interpret file %s as a pickle" % repr(file))
IOError: Failed to interpret file 'C.bin' as a pickle

我试图解决它，但我看不到更多。任何帮助表示赞赏。

注意：我有意使用np.load，因为稍后我会将数据集从磁盘加载到numpy数组中以便进一步处理。

Answer 1

您应该使用numpy中构建的save方法将数组存储在文件中。这是您的代码应该是什么样的：

for _ in range(5):
    C = np.random.rand(1, 5)
    r = np.random.rand(1, 5)

    np.save('C', C)
    np.save('r', r)

    # Now printing to check if appending is successful
    C = np.load("C.npy")
    r = np.load("r.npy")
    print (C)
    print (r)
    del C, r

请参阅文档https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.load.html

将numpy数组附加到两个二进制文件中

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