{
"list": [
{
"id": 62,
"user_id": "34",
"updated_at": "2017-10-15 08:24:32",
"request": {
"data": "yes",
"watch": "Pending"
}
},
{
"id": 63,
"user_id": "34",
"updated_at": "2017-10-15 08:24:32",
"request": {
"data": "yes",
"watch": "Yes"
}
}, ]
}
如何在update_at下获取监视值 如预期的那样
"list": [
{
"id": 62,
"user_id": "34",
"updated_at": "2017-10-15 08:24:32",
"watch": "Pending"
}..
我尝试使用array_column但不适合我。
function array_column($array, $column){
$ret = array();
foreach($array as $row){
$ret[] = $row[$column];
return $ret;
}
}
答案 0 :(得分:0)
有点像
function updateArray(&$array){
foreach($array['list'] as $key => $item){
$array['list'][$key]['watch'] = $item['request']['watch'];
unset($array['list'][$key]['request']);
}
}
updateArray($array);
print_r($array);
答案 1 :(得分:0)
我假设你知道你需要首先解码JSON:
$array = json_decode($json, true);
然后访问list
元素下的数组:
$result = array_column($array['list'], 'updated_at');
答案 2 :(得分:0)
这是一个很好的挑战。你在哪里
<pre>
<?php
$array=array("list"=>array(array("id"=>"62","user_id"=>"32","updated_at"=>2017,"request"=>array("data"=>"yes","watch"=>"panddin")),
array("id"=>"60","user_id"=>"30","updated_at"=>2016,"request"=>array("data"=>"no","watch"=>"pan"))));
//print_r($array);
foreach($array as $row){
foreach ($row as $key => $value){
if((is_array($value))){
foreach ($value as $key1 => $k){
if((is_array($k))){
foreach ($k as $key2 => $value2) {
echo $key2."=>". $value2."<br>";
}
}else echo $key1."=>".$k."<br>";
}
}else echo $key."=>".$value. "<br>";
}
}
?>
</pre>