Question

假设我有一个包含此数据的表（数据帧）：

| user     | food          |
|:--------:|:-------------:|
| 'A'      | 'meat'        | 
| 'A'      | 'carrot'      |
| 'A'      | 'candy'       |
| 'B'      |  'meat'       |
| 'B'      |  'carrot'      |
| 'C'      |  'meat'       |
| 'C'      |  'carrot'     |

代码：

df = pd.DataFrame({
    "user":["A", "A", "A", "B", "B", "C", "C"],
    "food":['meat', 'carrot', 'candy', 'meat', 'carrot', 'meat', 'carrot']
})

我想要建立的是一张桌子，每张食物告诉我拥有它们的用户数量：

| food 1     | food 2        |  num users | 
|:----------:|:-------------:|:----------:| 
| 'meat'     | 'carrot'      | 3          | 
| 'meat'     | 'candy'       | 1          | 
| 'carrot'     | 'candy'       | 1          |

有办法做到这一点吗？

Answer 1

您可以先使用get_dummies：

df = pd.get_dummies(df.set_index('user'), prefix='', prefix_sep='').max(level=0)
print (df)
      candy  carrot  meat
user                     
A         1       1     1
B         0       1     1
C         0       1     1

然后按list comprehension计算：

from  itertools import combinations

L = [(x[0], x[1],(df[list(x)] == 1).all(1).sum()) for x in list(combinations(df.columns, 2))]
print (L)
[('candy', 'carrot', 1), ('candy', 'meat', 1), ('carrot', 'meat', 3)]

df = pd.DataFrame(L, columns=['food 1','food 2','num users'])
print (df)
   food 1  food 2  num users
0   candy  carrot          1
1   candy    meat          1
2  carrot    meat          3

Answer 2

你可以试试这个：

food_pairs = [("meat", "carrot"), ("meat", "candy")]

food_to_users = {food: set(df.user[df.food == food].unique()) for food in df.food.unique()}

out = pd.DataFrame(
    ((*pair, len(set.intersection(*(food_to_users[food] for food in pair)))) for pair in food_pairs),
    columns=["food1", "food2", "num users"]
)

超过1000次试验的平均运行时间为0.00256s。

测试可伸缩性代码：

import itertools
import math
import pandas as pd
from random import shuffle
from timeit import time

SIZE_OF_PAIRS = 2
NUM_FOODS = 50
NUM_USERS = 1000
NUM_RECORDS = 100000

foods = (list(range(NUM_FOODS)) * (math.ceil(NUM_RECORDS/NUM_FOODS)))[:NUM_RECORDS]
users = (list(range(NUM_USERS)) * (math.ceil(NUM_RECORDS/NUM_USERS)))[:NUM_RECORDS]

shuffle(foods)
shuffle(users)

df = pd.DataFrame({"user": users, "food": foods})

food_pairs = pd.Series([*itertools.combinations(df.food.unique(), SIZE_OF_PAIRS)])

start = time.time()

food_to_users = {food: set(df.user[df.food == food].unique()) for food in df.food.unique()}
out = pd.DataFrame(
    ((*pair, len(set.intersection(*(food_to_users[food] for food in pair)))) for pair in food_pairs),
    columns=[*["food" + str(i) for i in range(SIZE_OF_PAIRS)], "num users"]
)

print("Time taken: {}s".format(time.time() - start))

熊猫：对来自同一列的夫妇进行分组

2 个答案: