OneToOne eclipseLink

Question

我想在PatientEntity和MonitoringEntity之间创建一个oneToOne关系，但我有这个错误：实体类[class ch.lestoises.monitopsy.medication.entity.MonitoringEntity]中的属性[patient]的mappedBy值为[monitoringCode]在其拥有的实体类[class ch.lestoises.monitopsy.patient.entity.PatientEntity]中不存在。如果拥有的实体类是@MappedSuperclass，则这是无效的，并且您的属性应该引用正确的子类。这是我的代码：

@Entity
@Table(name = "patient")
@XmlRootElement
@NamedQueries({
    @NamedQuery(name = "PatientEntity.findByNumber", query = "SELECT p FROM PatientEntity p WHERE p.patientNumber = :number"),
    @NamedQuery(name = "PatientEntity.findAllPatient", query = "SELECT p FROM PatientEntity p ")
})
public class PatientEntity implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "pk_patient")
    private Integer pkPatient;

    @NotNull
    @Column(name = "name")
    private String name;

    @NotNull
    @Column(name = "firstname")
    private String firstname;

    @OneToOne
    @JoinColumn(name="pk_monitoring")
    private transient MonitoringEntity monitoringCode;
} the Monitoring class : @Entity
public class MonitoringEntity {

    @Id
    @Column(name = "pk_monitoring")
    private Integer pkMonitoring;

    @OneToOne(mappedBy="monitoringCode")
    private PatientEntity patient;
}

Answer 1

我应该在PatientEntity中删除现场监控的瞬态和@JoinColumn