我想从没有RSS Feed的新闻网站获取数据,我只想获得标题名称,而我正在使用此代码 -
var url = NSURL(string: "http://www.gulf-times.com/stories/c/192/0/Sport")
if url != nil {
let task = URLSession.shared.dataTask(with: url! as URL, completionHandler: { (data, response, error) -> Void in
print(data)
if error == nil {
var urlContent = NSString(data: data!, encoding: String.Encoding.ascii.rawValue) as NSString!
print(urlContent)
}
})
task.resume()
}
问题是,我无法获得标题值
答案 0 :(得分:1)
如果您对RegEx感到满意,请使用以下模式
/title = "(.*)"/g
这将为您提供所有标题。
<强>修改:强>
请使用如下
let matched = matches(for: "title = \"(.*)\"", in: contentOfPage)
匹配:功能
func matches(for regex: String, in text: String) -> [String] {
do {
let regex = try NSRegularExpression(pattern: regex)
let results = regex.matches(in: text,
range: NSRange(text.startIndex..., in: text))
return results.map {
String(text[Range($0.range, in: text)!])
}
} catch let error {
print("invalid regex: \(error.localizedDescription)")
return []
}
}
获得以下结果
[
"title = \"Al-Khelaifi voted Asian tennis Chairman\"",
"title = \"Dimitrov downs Goffin for ATP Tour Finals crown\"",
"title = \"Coach Lehmann calls for Australia to get behind Ashes selection\"",
"title = \"Federer expects great things from returning trio\"",
"title = \"Whateley wins Air Maroc League second stage\"",
"title = \"Qatar-based Frijns finishes strong as Oliphant wins\"",
"title = \"Sutton faces tough road ahead to get Chinese on track\"",
"title = \"Qatar, Japan sign deal to import, export race horses\"",
"title = \"Islanders deny Lightning comeback for third straight win\"",
"title = \"Curry leads Golden Warriors fightback after Sixers blitz\"",
"title = \"Fleetwood claims European Order of Merit as Rose falters\"",
"title = \"Challengers win thriller against City Exchange\""
]
答案 1 :(得分:0)
你得到url的响应是String
然后只是将字符串解析为子字符串。
例如,标题是var title =
和var brief =
之间的子字符串。
像split
或components(separatedBy:_)
等字符串方法可以实现。