Question

那么描述我想要做的事情有点复杂，让我完全解释一下。首先，我从多个选择中选择了一个或多个选项并将其内嵌到一列中，现在我希望在一列中显示每个选择ID名称。

第一次内爆：

$gallery_category = implode('  ',$_POST['gallery_category']);

然后尝试显示每个唯一ID名称，如此

$gallery_category = $row['gallery_category'];
$output = explode(" ", $gallery_category);
$query = 'SELECT * FROM  gallery_category WHERE gallery_category_name2 = "'.$output.'"';
$select_categories_name = mysqli_query($connection,$query);  

while($row = mysqli_fetch_assoc($select_categories_name)) {
    $gallery_category_name = $row['gallery_category_name'];
    echo "<td> $gallery_category_name</td>";
}

得到如下错误：注意：数组转换为字符串

Answer 1

$gallery_category = $row['gallery_category'];
$output = explode(" ", $gallery_category);//this is an array so have to give it in a loop or specify by index 
foreach($output as $category)
{   
    $query = 'SELECT * FROM  gallery_category WHERE gallery_category_name2 = "'.$category.'"';
    $select_categories_name = mysqli_query($connection,$query);         
        while($row = mysqli_fetch_assoc($select_categories_name)) {
            $gallery_category_name = $row['gallery_category_name'];
            echo "$gallery_category_name";    
        }
}

这应该有用，如果没有请注释。

是否可以从一列中的ID组合中选择n显示每个ID名称？

1 个答案: