使用Mutex跟踪另一个应用程序的生命周期

时间:2017-11-19 21:11:12

标签: c# c++ mutex

MyApp1(C#)启动MyApp2(C#)。当MyApp2完全启动时,它会执行:

new Mutex(true, "MyApp2IsRunning");

与此同时,MyApp1一直在等待这种情况发生:

Mutex myApp2Mutex = null;
while (myApp2Mutex == null && !timedOut)
{
   try
   {
      myApp2Mutex = Mutex.OpenExisting("MyApp2IsRunning");
   }
   catch(WaitHandleCannotBeOpenedException)
   {
      Thread.Sleep(100);
   }
}
if (timedout) {return error;}
myApp2Mutex.WaitOne();

因此,如果MyApp2在规定的时间内启动,MyApp1现在会等待MyApp2IsRunning互斥锁,以了解用户何时退出MyApp2。

我只用C ++重写MyApp1。检测MyApp2状态的等效Mutex相关代码是什么?因此MyApp1仍将负责启动MyApp2,我仍然希望它能够检测MyApp2何时启动以及用户何时退出MyApp2。与上面相同的代码,但在C ++中。

2 个答案:

答案 0 :(得分:0)

一个简单的谷歌搜索给你:

HANDLE mutex_you_want = CreateMutex(nullptr,true,“MyApp2IsRunning”);

答案 1 :(得分:0)

此伪代码使MyApp1能够等待MyApp2启动,然后检测用户何时退出MyApp2:

HANDLE hMutex = nullptr;
while (hMutex == nullptr && !timedout)
{
    hMutex = OpenMutex(
        SYNCHRONIZE,
        FALSE,
        "MyApp2IsRunning");
    Sleep(1000);
}
if (timedout){return error;}
DWORD wait_result = WaitForSingleObject(hMutex, INFINITE);