Question

我有这段代码：

include "config.php";
if (isset($connect)) {
    echo "connected";
} else {
    echo "not connected";
}

这是config.php文件：

$localhost = "localhost";
$db_username = "*****";
$db_password = "*****";
$db_name = "*****"; 
If($connect = mysqli_connect("$localhost ","$db_username ","$db_password ","$db_name ")){}or die{}

我不知道为什么，但是当我尝试做一些查询时，我没有得到任何东西

$sql="SELECT * FROM table_name ORDER BY column_name ASC";
$query=($connect,$sql);
While($row = mysqli_fetch_object($query)) {
    Echo $row>column;
}

错误是：

 Parse error: syntax error, unexpected '}' in /path/index.php on line 6

Answer 1

我在您的代码中看到了多个问题，

首先来自config.php

If($connect = mysqli_connect("$localhost ","$db_username ","$db_password ","$db_name ")){}or die{}

这不是正确的代码，{}or die{}中的错误必须是{} else {die();}

但我建议你改用这个，

$connect = mysqli_connect("$localhost", "$db_username", "$db_password", "$db_name") or die(mysqli_connect_error());

关于第三个代码有一些问题，首先是

$query=($connect,$sql);

你忘了使用mysqli_query

$query=mysqli_query($connect, $sql);

在打印数据时，您必须使用->而不是>

Echo $row->column;

我希望这会有所帮助。

当连接正确时，无法从数据库中获取数据

1 个答案: