%% Gram—Schmidt as Triangular Orthogonalization
clear
M = [1,1,1; 1,1,0; 1,1,9]
[m,n] = size(M);
Q = M;
Rinv = eye(n);
for i = 1:n
Ri = eye(n);
Ri(i,i) = 1 / norm(Q(:,i));
for j = i+1:n
Ri(i,j) = -Q(:,i)'*Q(:,j) / norm(Q(:,i));
end
Q = Q*Ri;
Rinv = Rinv*Ri;
end
Q
R = inv(Rinv)
问题:Q*R
给出了M
,但Q
不是正对角线。
答案 0 :(得分:0)
这应该返回正确的结果:
clear();
M = [1,1,1; 1,1,0; 1,1,9];
[m,n] = size(M);
Q = zeros(m,n);
R = zeros(n,n);
for j = 1:n
v = M(:,j);
for i = 1:j-1
R(i,j) = Q(:,i).' * M(:,j);
v = v - (R(i,j) * Q(:,i));
end
R(j,j) = norm(v);
Q(:,j) = v / R(j,j);
end
或者,您可以尝试我在Matlab文件交换中找到的以下实现(它包含许多已知的算法变体):https://it.mathworks.com/matlabcentral/fileexchange/55881-gram-schmidt-orthogonalization