如何从目标c中的UITableViewCell获取2个输入值

Question

我需要从相同的NSMutableArray中获取2个输入值，例如textfield 1和textfield 2 [score 1，score 2]，并将这些值添加到字典中并将这些字典数据添加到- (void)textFieldDidEndEditing:(UITextField *)textField{ UITableViewCell *cell = (UITableViewCell*) textField.superview.superview; NSIndexPath *txtIndPath = [tblMonthlyPerformanceReport indexPathForCell:cell]; MonthlyPerformanceQuestions * question; if (txtIndPath.section==0) { question = [[HSEAppData appData].arrayMonthlyGeneralQustion objectAtIndex:txtIndPath.row]; } if (txtIndPath.section==1) { question = [[HSEAppData appData].arrayMonthlyLeadQustion objectAtIndex:txtIndPath.row]; } if (txtIndPath.section==2) { question = [[HSEAppData appData].arrayMonthlyLagQustion objectAtIndex:txtIndPath.row]; } NSLog(@"%@ , %@",question.QuestionId, question.Question); NSMutableDictionary *userDictionary=[[NSMutableDictionary alloc]init]; [userDictionary setObject:question.QuestionId forKey:@"question"]; if (textField.tag==10001) { [userDictionary setObject:textField.text forKey:@"score1"]; } if (textField.tag==10002) { [userDictionary setObject:textField.text forKey:@"score2"]; } [scoreMutableArray addObject:userDictionary];

我在下面的代码中使用了文本字段委托方法..

{
question = a5k0k0000004kxsAAA;
score2 = 5;
}

我收到了回复

{
                "question": "a5k0k0000004kxnAAA", 
                "score1": "20", 
                "score2": "20"
            }

我将数据放在得分1上，但数据得分为2 我需要像这样的字典数据

/*CREATE TOP AND BOTTOM CLAUSES*/
/*Top Clauses*/
const addClauseTop = document.querySelector('#addClauseTop');
var targetClauseElement;
var addDetail = document.getElementById('addDetail');
addDetail.addEventListener('focusin', function(e) {
  createDetail(e.relatedTarget);
});

window.addEventListener('mouseup',function(e) {
	if ( e.currentTarget != addDetail ) {
			addDetail.style.display='none';
	}
});


var firstTopClause = document.getElementsByClassName('clause')[0];
firstTopClause.addEventListener('click', function(e) {
  addDetail.style.display='inline-block';
}); 

var firstBottomClause = document.getElementsByClassName('clauseDivReverse')[0];
firstBottomClause.addEventListener('click', function(e) {
  addDetail.style.display='inline-block';
}); 



addClauseTop.addEventListener('click',function(e){
	e.preventDefault();
	//Get Divs-Overlay
	const topDivs = document.querySelector('#topClauses');
	const bottomDivs = document.querySelector('#bottomClauses');

	// Create Elements
	const clauseDiv = document.createElement('div');
	const clauseText = document.createElement('input');
	const clauseStroke = document.createElement('div');
  
	// // //Give Style
	clauseDiv.classList.add('clauseDiv');
  clauseDiv.addEventListener('click', function(e) {
    addDetail.style.display='inline-block';
  }); 
	clauseText.classList.add('clause');
	clauseText.setAttribute("id", "clause");
	clauseStroke.classList.add('strokeClause');
  //
	// // Append to document
	clauseDiv.appendChild(clauseText);
	clauseDiv.appendChild(clauseStroke);
	topDivs.appendChild(clauseDiv);
	document.body.appendChild(topDivs);
	document.body.appendChild(bottomDivs);
  
})
/*BOTTOM Clauses*/
const addClauseBottom = document.querySelector('#addClauseBottom');
addClauseBottom.addEventListener('click',function(e){
	e.preventDefault();
	//Get Divs-Overlay
	const topDivs = document.querySelector('#topClauses');
	const bottomDivs = document.querySelector('#bottomClauses');

	// Create Elements
	const clauseDiv = document.createElement('div');
  clauseDiv.addEventListener('click', function(e) {
    targetClauseElement = e.currentTarget; 
    addDetail.style.display='inline-block';
  }); 
	const clauseText = document.createElement('input');
	const clauseStroke = document.createElement('div');

	// // //Give Style
	clauseDiv.classList.add('clauseDivReverse');
	clauseText.classList.add('clauseReverse');
		clauseText.setAttribute("id", "clauseReverse");
	clauseStroke.classList.add('strokeClauseReverse');
  //
	// // Append to document
	clauseDiv.appendChild(clauseText);
	clauseDiv.appendChild(clauseStroke);
	bottomDivs.appendChild(clauseDiv);
	document.body.appendChild(bottomDivs);
})
/***********/



//Create a addDetail
function createDetail(target){

      var mainColumn = target.parentElement;
      var strokeColumn = mainColumn.children[1];
      // Create Elements
      var levelOneDiv = document.createElement('div');
      var levelOneText = document.createElement('input');

      if ( mainColumn.classList.contains('clauseDiv') ) {
      	 levelOneDiv.classList.add('levelOneClauseReverse');
         levelOneText.classList.add('levelOneTextReverse');
         //I thought you have not completed your style yet, like something levelOneClause class
      } else {
         levelOneDiv.classList.add('levelOneClauseReverse');
         levelOneText.classList.add('levelOneTextReverse');          
      }

      levelOneDiv.appendChild(levelOneText);
      strokeColumn.appendChild(levelOneDiv);

  }

请帮帮我

Answer 1

将Dictionary作为全局变量。在字典中添加每个值，然后在添加字典到数组时检查字典的数量（如果是3）则将字典添加到数组并在将字典添加为空后添加字典。