我刚添加了一个＆＃39; add＆＃39;之前具有包含“更新”按钮的“编辑”后，我的网格视图中的按钮，但是在添加“添加”按钮之后使用在gridview和数据库中添加的记录查看完美的按钮，编辑按钮似乎不再起作用。这是按钮的脚本。
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" CellPadding="6" OnRowCancelingEdit="GridView1_RowCancelingEdit"
OnRowEditing="GridView1_RowEditing" OnRowUpdating="GridView1_RowUpdating" Height="226px" Width="1172px" ShowFooter="True" HorizontalAlign="Center">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:Button ID="btn_Edit" runat="server" Text="Edit" CommandName="Edit" Font-Size="Medium" Height="32px" Width="68px" />
</ItemTemplate>
<EditItemTemplate>
<asp:Button ID="btn_Update" runat="server" Text="Update" CommandName="Update"/>
<asp:Button ID="btn_Cancel" runat="server" Text="Cancel" CommandName="Cancel"/>
</EditItemTemplate>
<FooterTemplate>
<asp:Button ID="newAddBtn" runat="server"
OnClick="NewAddBtn_Click" Text="Add" CommandName="Insert" Font-Size="Medium" Height="32px" Width="64px"/>
</FooterTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Class ID">
<ItemTemplate>
<asp:Label ID="lbl_CID" runat="server"
Text='<%#Eval("CID") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Class Name">
<FooterTemplate>
<asp:DropDownList ID="newName" runat="server">
<asp:ListItem>Select</asp:ListItem>
<asp:ListItem>Power Yoga</asp:ListItem>
<asp:ListItem>Pilates</asp:ListItem>
<asp:ListItem>Cardio Peak</asp:ListItem>
<asp:ListItem>Body Attack</asp:ListItem>
<asp:ListItem>Corb</asp:ListItem>
<asp:ListItem>Boxing</asp:ListItem>
<asp:ListItem>Zumba</asp:ListItem>
<asp:ListItem>Weights</asp:ListItem>
</asp:DropDownList>
<asp:RequiredFieldValidator ID="NameErr" runat="server"
ControlToValidate="newName" ErrorMessage="*" ForeColor="Red">
</asp:RequiredFieldValidator>
</FooterTemplate>
<ItemTemplate>
<asp:Label ID="lbl_cName" runat="server" Text='<%#Eval("CName") %>'></asp:Label>
</ItemTemplate>
<EditItemTemplate>
<asp:TextBox ID="cname_txt" runat="server" Text='<%#Eval("CName") %>'></asp:TextBox>
</EditItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Class Start Time">
<FooterTemplate>
<asp:TextBox ID="newStart" runat="server"></asp:TextBox>
<asp:RequiredFieldValidator ID="startErr" runat="server" ControlToValidate="newStart" ErrorMessage="*" ForeColor="Red"></asp:RequiredFieldValidator>
</FooterTemplate>
<ItemTemplate>
<asp:Label ID="lbl_cstart" runat="server" Text='<%#Eval("CStart") %>'></asp:Label>
</ItemTemplate>
<EditItemTemplate>
<asp:TextBox ID="cstart_txt" runat="server" Text='<%#Eval("cStart") %>'></asp:TextBox>
</EditItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Class Finish Time">
<FooterTemplate>
<asp:TextBox ID="newEnd" runat="server"></asp:TextBox>
<asp:RequiredFieldValidator ID="endErr" runat="server" ControlToValidate="newEnd" ErrorMessage="*" ForeColor="Red"></asp:RequiredFieldValidator>
</FooterTemplate>
<ItemTemplate>
<asp:Label ID="lbl_cend" runat="server" Text='<%#Eval("cend") %>'></asp:Label>
</ItemTemplate>
<EditItemTemplate>
<asp:TextBox ID="cend_txt" runat="server" Text='<%#Eval("cend") %>'></asp:TextBox>
</EditItemTemplate>
</asp:TemplateField>
</Columns>
<FooterStyle BackColor="#663300" />
<HeaderStyle BackColor="#663300" ForeColor="#ffffff"/>
<RowStyle BackColor="#e7ceb6"/>
</asp:GridView>
以下是＆＃34;添加＆＃34;背后的代码。按钮，在连接打开到数据库之后。
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
ShowData();
}
}
//ShowData method for Displaying Data in Gridview
protected void ShowData()
{
dt = new DataTable();
con = new SqlConnection(cs);
con.Open();
// adapt = new SqlDataAdapter("Select * from customers", con);
adapt = new SqlDataAdapter("Select * from classes", con);
adapt.Fill(dt);
if (dt.Rows.Count > 0)
{
GridView1.DataSource = dt;
GridView1.DataBind();
}
con.Close();
}
Control control = null;
if (GridView1.FooterRow != null)
{
control = GridView1.FooterRow;
}
else
{
control = GridView1.Controls[0].Controls[0];
}
string className = ((DropDownList)GridView1.FooterRow.FindControl("newName")).SelectedItem.Text;
// string className = (GridView1.FooterRow.FindControl("newName") as TextBox).Text;
string startTime = (GridView1.FooterRow.FindControl("newStart") as TextBox).Text;
string endTime = (GridView1.FooterRow.FindControl("newEnd") as TextBox).Text;
// string strConnString = ConfigurationManager.ConnectionStrings["strcon"].ConnectionString;
// using (SqlConnection con = new SqlConnection(strConnString))
cmd.Connection = con;
cmd.CommandType = CommandType.Text;
cmd.CommandText = "INSERT INTO classes VALUES(@cName, @cStart, @cEnd)";
cmd.Parameters.AddWithValue("@cName", className);
cmd.Parameters.AddWithValue("@cStart", startTime);
cmd.Parameters.AddWithValue("@cEnd", endTime);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
// Response.Redirect(Request.Url.AbsoluteUri);
}
答案 0 :(得分：1)
您需要确保在添加操作结束时，您的gridview是数据绑定，如下面的代码段中所示，即在C＃代码中的con.Close();代码行之后。
我假设你有一个获取gridviewdata的方法。
GridView1.DataSource = GetGridData();
GridView1.DataBind();
此外，请确保页脚中的所有验证程序都具有ValidationGroup =＆＃34;添加＆＃34;否则当您单击网格行中的“编辑”按钮时，它将阻止页脚回发，因为页脚验证程序。另外，添加ValidationGroup =＆＃34; Add＆＃34;对于“添加”按钮也是。
<FooterTemplate>
<asp:TextBox ID="newEnd" runat="server"></asp:TextBox>
<asp:RequiredFieldValidator ID="endErr" runat="server" ValidationGroup="Add"
ControlToValidate="newEnd" ErrorMessage="*" ForeColor="Red"></asp:RequiredFieldValidator>
</FooterTemplate>